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Gre4nikov [31]
2 years ago
6

Analyze the diagram showing the changing states of matter. Drag the item from the item bank to its corresponding match.

Chemistry
1 answer:
iVinArrow [24]2 years ago
6 0

The correct matches for changes of state are:

  • 1 or 3 : Arrow that shows particles getting closer together
  • gas: State of matter that would fill any container
  • liquid: State of matter with definite volume but NOT shape
  • 2 or 4: Arrow that shows particles gaining energy
  • solid: State of matter with definite shape

<h3>What is change of state?</h3>

Change of state is the process whereby matter in one physical state is converted to matter in another state by the addition or removal of heat.

The process of change of state are:

  • Melting: solid to liquid due to addition of heat
  • Vaporization: liquid to gas due to addition of heat
  • Sublimation: solid to gas due to addition of heat
  • Freezing: liquid to solid due to removal of heat
  • Condensation: gas to liquid due to removal of heat
  • Deposition: gas to solid due to removal of heat

Considering the given diagram, the correct matches are:

  • 1 or 3 : Arrow that shows particles getting closer together
  • gas: State of matter that would fill any container
  • liquid: State of matter with definite volume but NOT shape
  • 2 or 4: Arrow that shows particles gaining energy
  • solid: State of matter with definite shape

In conclusion, change of state of matter occurs due to heat changes.

Learn more about change of state at: brainly.com/question/1078692

#SPJ1

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To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

6 0
3 years ago
How many grams of O₂ are required to react completely with 14.6 g of Na to form sodium oxide, Na₂O?
Bad White [126]

The balanced chemical reaction is :

O_2 + 4Na \ -> \ 2Na_2O

Number of moles of Na, n = \dfrac{14.6}{23} = 0.635 \  mol .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

n = \dfrac{0.635}{4}\  mole

So, amount of oxygen required is :

m = \dfrac{0.635 \times 32}{4}\  gm\\\\m = 5.08 \ gm

Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

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3 years ago
A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of
ICE Princess25 [194]

Answer:

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = V_1=10.0 L

Initial pressure of the gas = P_1=4.0 atm

Final volume of the gas = V_2=5.0 L

Final pressure of the gas = P_2=8.0 atm

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

P_1\propto \frac{1}{V_1}

P_1V_1=k_i

k_i=4.0 atm\times 10.0 L = 40.0 atm L

P_2\propto \frac{1}{V_2}

P_V_2=k_f

k_f=8.0 atm\times 5.0 L = 40.0 atm L

k_i=k_f=40.0 atm L

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

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