First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of $HNO_{3}$ .

Explanation:

In presence of NaCl, $AgNO_{3}$ forms an insoluble precipitate of AgCl.

Reaction: $Ag^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)$

In presence of $NH_{3}$ , AgCl gets dissolved into solution due to formation of soluble $[Ag(NH_{3})_{2}]^{+}$ complex.

Reaction: $AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)$

In presence of $HNO_{3}$ , $[Ag(NH_{3})_{2}]^{+}$ complex gets destroyed and free $Cl^{-}$ again reacts with free $Ag^{+}$ to produce insoluble AgCl

Reaction: $[Ag(NH_{3})_{2}]^{+}(aq.)+2H^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)+2NH_{4}^{+}(aq.)$

4 0

2 years ago

An element is a pure substance. It can not easily be broken down into parts by physical means.

liberstina [14]

Answer: An element is a pure substance. It can not easily be broken down into parts by physical means.

A)True

B)False

<u>The answer is true. </u>

7 0

3 years ago

You drop a rock weighing 23.2 g into a graduated cylinder that contains 55 mL. The level

snow_lady [41]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 23.2 g

volume = final volume of water - initial volume of water

volume = 62 - 55 = 7 mL

We have

$density = \frac{23.2}{7} \\ = 3.314285$

We have the final answer as

Hope this helps you

8 0

3 years ago