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3 years ago

Which of the following are examples of chemical energy being released or stored? (2 points)

1 answer:

3 0

A boy eating a orange to survive because it’s going in his stomach and the sun heating a rock because Heat from the sun causes rock to crack or buckle from pressure caused by its atoms' increasing speed.

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A temperature of 55°F is approximately equivalent to 13°C.

GuDViN [60]

Answer: Yes. That is right. The actual answer, not rounded, would be 12.7778 Degrees Celsius.

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3 years ago

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kumpel [21]

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Explanation

<h2>#KEEPSTUDYING</h2><h2 />

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What substances decrease the h+ ion concentration in a solution?

marusya05 [52]

Acid is 1. a substance that increases the hydrogen ion concentration of a solution
<span>2. removes hydroxide ions because of the tendency for H+ to combine with OH-</span>

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3 years ago

Since the half-life of 235U (7. 13 x 108 years) is less than that of 238U (4.51 x 109 years), the isotopic abundance of 235U has

Ymorist [56]

Answer:

$\mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}$

Explanation:

Given that:

The Half-life of $^{235}U$ = $7.13 \times 10^8 \ years$ is less than that of $^{238} U = 4.51 \times 10^9 \ years$

Although we are not given any value about the present weight of $^{235}U$ .

So, consider the present weight in the percentage of $^{235}U$ to be y%

Then, the time elapsed to get the present weight of $^{235}U$ = $t_1$

Therefore;

$N_1 = N_o e^{-\lambda \ t_1}$

here;

$N_1$ = Number of radioactive atoms relating to the weight of y of $^{235}U$

Thus:

$In( \dfrac{N_1}{N_o}) = - \lambda t_1$

$In( \dfrac{N_o}{N_1}) = \lambda t_1$ --- (1)

However, Suppose the time elapsed from the initial stage to arrive at the weight of the percentage of $^{235}U$ to be = $t_2$

Then:

$In( \dfrac{N_o}{N_2}) = \lambda t_2$ ---- (2)

here;

$N_2$ = Number of radioactive atoms of $^{235}U$ relating to 3.0 a/o weight

Now, equating equation (1) and (2) together, we have:

$In( \dfrac{N_o}{N_1}) -In( \dfrac{N_o}{N_2}) = \lambda( t_1-t_2)$

replacing the half-life of $^{235}U$ = $7.13 \times 10^8 \ years$

$In( \dfrac{N_2}{N_1}) = \dfrac{In 2}{7.13 \times 10^9}( t_1-t_2)$ ( since $\lambda = \dfrac{In 2}{t_{1/2}}$ )

∴

$\mathtt{In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2}= t_1-t_2}$

The time elapsed signifies how long the isotopic abundance of 235U equal to 3.0 a/o

Thus, The time elapsed is $\mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}$

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3 years ago

PLEASE HURRY!!!

Bezzdna [24]

Answer:

<em><u>Measurement of the amount of variation of the species in a given area. </u></em>

Explanation:

<em>Bio</em> preffix means life. Thus, literally, biodiversity means how diverse is the life. This is, how many different organisms an ecosystem or biome has.

Thus, biodiverstiy, although more complex than just that, is a measure of the number of species that live in a region.

The biome with most species than any other, this is the biome with the greatest biodiversity, is the tropical rainforest biome, which are located near the equator. As you can imagine, a large number of different plants, animals, and microorganisms live in these forests, making them the regions with greatest biodiversity on the planet.

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