Question

the sum of three numbers is 128.The third number is 10 more than the first .The second number 4 times the third number. what are the numbers

Answer 1

128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a

1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23