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irina [24]
3 years ago
10

On some engines, after torquing cylinder head fasteners, you

Engineering
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

Re-torque the bolts as required while your engine is warm. But if you're using aluminum cylinder heads, you should wait until your engine is complete cooled until re-torquing

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What do we need to do to get CO2 emissions all the way to zero?
Svetlanka [38]

Answer:

A key element is powering economies with clean energy, replacing polluting coal - and gas and oil-fired power stations - with renewable energy sources, such as wind or solar farms. This would dramatically reduce carbon emissions. Plus, renewable energy is now not only cleaner, but often cheaper than fossil fuels

Explanation:

here is your answer if you like my answer please follow

3 0
3 years ago
ceramics must be heated in order to harden the clay and make it durable. the equipment used to heat the clay
SIZIF [17.4K]

Ceramics must be heated in order to harden the clay and make it durable. The tool used to heat the clay is called a Kiln.

<h3>What happens when ceramic is heated?</h3>

Cristobalite is a silica polymorph that is used in ceramics. Quartz particles in porcelain can change into cristobalite during burning. This has effects on the fired matrix's thermal expansion. When there is a high level of vitrification or a shape is unstable during the firing of ceramic ware, warping occurs.

Ceramic items are porous, brittle, and rigid. They are thus employed in the production of glass, ceramics, cement, and bricks. Additionally, ceramics are employed extensively in gas turbine engines. Artificial bones and dental implants are both made of bio-ceramics.

Any of the several tough, fragile, heat- and corrosion-resistant materials created by sculpting and then heating an inorganic, nonmetallic material like clay to a high temperature are known as ceramics.

In order to solidify the clay and make ceramics durable, heat must be applied. A kiln is the name of the device used to heat clay.

To learn more about ceramics refer to:

brainly.com/question/26247382

#SPJ4

5 0
2 years ago
The end of a cylindrical liquid cryogenic propellant tank in free space is to be protected from external (solar) radiation by pl
prohojiy [21]

If the temperature of the shield is 338 kelvin. Then the heat flux through the tank will be 25.3 Watt per square meter.

<h3>What is heat flux?</h3>

The increase in heat energy movement through a particular surface is known as heat flux, and the heat flux density is the absolute temperature per unit area.

Assume the view factor between the tank and the shield is unity; all surfaces are diffuse and gray, and the surroundings are at 0 K.

It is given that T= 100 K, ε₁ = ε₂ = 0. 10, \varepsilon_t = 0.20, and GS= 1250 W/m².

Then we have

The temperature of the shield will be

\rm \alpha _sG_s - \varepsilon _1 E_b (T_s) - \dot{q}_{ST} = 0 ...1

and

\rm q''_{12}=\dfrac{ \sigma (T_{1}^{4} - T_{2}^{2})}{\frac{1}{\varepsilon _1 }+ \frac{1}{\varepsilon _2} -1}} ...2

Then from equations 1 and 2, we have

\rm \alpha _sG_s - \varepsilon _1 E_b (T_s) - \dfrac{ \sigma (T_{1}^{4} - T_{2}^{2})}{\frac{1}{\varepsilon _1 }+ \frac{1}{\varepsilon _2} -1}} = 0

Then the value of \rm T_s will be

\rm T_s =\left [ \dfrac{\alpha _sGs+\left ( \dfrac{\sigma T_1^4}{\frac{1}{\varepsilon _1}+\frac{1}{\varepsilon _2} - 1} \right )}{\sigma \left ( \varepsilon _1 + \dfrac{1}{\frac{1}{\varepsilon _1} + \frac{1}{\varepsilon _2}-1} \right )} \right ] ^{\dfrac{1}{4}}

Put all the values, then we have

\rm T_s = \left [ \dfrac{0.05 \times + \left ( \dfrac{\sigma (100)^4}{\frac{1}{0.1}+\frac{1}{0.05}-1} \right )}{\sigma \left ( 0.05 + \dfrac{1}{\frac{1}{0.1}+\frac{1}{0.05} - 1} \right )} \right ]^{\dfrac{1}{4}} \\\\\\T_s = 338 \ K

Then the heat flux will be

\rm q"_{ST}=\dfrac{\sigma (T_S^4 - T_t^4)}{\frac{1}{\varepsilon _1} + \frac{1}{\varepsilon _2} - 1} \\\\\\q"_{ST}=\dfrac{5.67 \times 10^{-8}(388^4-100^4)}{\frac{1}{0.1}+\frac{1}{0.05}-1}\\\\\\q"_{ST} = 25.3 \ W/m^2

More about the heat flux link is given below.

brainly.com/question/12913016

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8 0
3 years ago
How does an airfoil create lift?
scoundrel [369]

Answer:

An airfoil creates lift by exerting a downward force on the air as it flows past

3 0
3 years ago
Air flows steadily and isentropically from standard atmospheric conditions to a receiver pipe through a converging duct. The cro
Liula [17]

Answer:

The answer is "0.0728"

Explanation:

Given value:

P_0= 14.696\ ps\\\\\ p _{0}= 0.00238 \frac{slue}{ft^{3}}\\\\\ A= 0.05 ft^2\\\\\ T_0= 59^{\circ}f = 518.67R\\\\\ air \ k= 1\\\\ \ cirtical \  pressure ( P^*)=P_0\times \frac{2}{k+1}^{\frac{k}{k-1}}\\

                                     = 14.696\times (\frac{2}{1.4+1})^{\frac{1.4}{1.4-1}}\\\\=7.763 Psia\\\\

if P flow is chocked

if P>P^{*} \to flow is not chocked

When  P= 10 psia < P^{*} \to not chocked

match number:

\ for \ P= \ 10\ G= \sqrt{\frac{2}{k-1}[(\frac{\ p_{0}}{p})^{\frac{k-1}{k}}-1]}

                       = \sqrt{\frac{2}{1.4-1}[(\frac{14.696}{10})^{\frac{1.4-1}{1.4}}-1]}

M_0=7.625

p=p_0(1+\frac{k-1}{2} M_0 r)^\frac{1}{1-k}

  =0.00238(1+\frac{1.4-1}{2}0.7625`)^{\frac{1}{1-1.4}}\\\\\ p=0.001808 \frac{slug}{ft^3}

\ T= T_0(1+\frac{k-1}{2} Ma^r)^{-1}\\\\\ T=518.67(1+\frac{1.4-1}{2} 0.7625^2)^{-1}\\\\\ T=464.6R\\\\

\ velocity \ of \ sound \ (C)=\sqrt{KRT}\\\\

                                    =\sqrt{1.4\times1716\times464.6}\\\\=1057 ft^3\\\\

R= gas constant=1716

m=PAV\\\\

    =0.001808\times0.05\times(Ma.C)\\\\=0.001808\times0.05\times0.7625\times 1057\\\\=0.0728\frac{slug}{s}

5 0
3 years ago
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