Answer:
0.30M HOAc
Explanation:
Given 250.0ml (0.96M HOAc) => 800ml(??M HOAc)
Use the dilution equation...
(Molarity x Volume)concentrated soln = (Molarity x Volume)dilute soln
(0.96M)(250.0ml) = (Molarity diluted soln)(800ml)
Molarity diluted soln = (0.96M)(250.0ml)/(800ml) = 0.30M HOAc
The number of grams of copper reacted is 445 grams
<u><em>calculation</em></u>
2Cu +O₂ → 2CuO
from equation above the mole ratio of Cu:CUO is 2:2 =1:1, therefore the moles of Cu is also= 7.00 moles
mass=moles x molar mass
from periodic table the molar mass of Cu= 63.5 g/mol
mass= 7.00 moles x 63.5 g/mol =445 grams
Probably About 2 or 3 more
Answer:
Kb is termed as Ebullioscopic constant.
Explanation:
According to Boiling point elevation phenomenon, any solution will be exhibiting higher boiling point compared to its pure solvent. So this increase in the boiling point of any liquid when a solute is added in the host is termed as boiling point elevation phenomenon. Thus, the boiling point elevation should be related with the molality of the solution b . So the ratio of increase in the boiling point or the boiling point elevation temperature to the molality of the solution gives a constant termed as ebullioscopic constant and denoted as Kb. In other words, we can state the boiling point elevation temperature is directly proportional to the molality of solution with Kb as proportionality constant.
Answer:
180.845 mol
Explanation:
Molar mass of Ca: 40,078 g/mol
Molar mass of C: 12,0107 g/mol
Molar mass of O: 15,999 g/mol
Molar mass of CaCO3: (40,078+12,0107+3×15,999) 100,0857 g/mol
The number of moles= mass of bag in g ÷ molar mass of CaCO3
⇒ n= (18.1×1000)÷100,0857 = 180.845 mol