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Anvisha [2.4K]
3 years ago
5

NEED HELP ASAP!!! What is the density of each of the following gases at STP? Show your work.

Chemistry
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

A. 1.63g/dm^3 (3 s.f.)

B. 0.833g/dm^3 (3 s.f.)

C. 1.92g/dm^3 (3 s.f.)

Explanation:

Please see attached picture for full solution.

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Can I find a tutor to help me with this question?
Eddi Din [679]

INFORMATION:

We have the following statements

And we must complete them

STEP BY STEP EXPLANATION:

To complete the statements, we need to classify matter according to its state:

- Solid:

there is not enough thermal energy to overcome the intermolecular interactions between the particles. As a result, solids have a definite shape and volume.

- Liquid:

That describes the liquid state. In a liquid, the particles are still in close contact, so liquids have a definite volume. However, because the particles can move about each other rather freely, a liquid has no definite shape and takes a shape dictated by its container.

- Gas:

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Finally, we know that:

- A solid has a definite volume and has a definite shape

- A liquid has a definite volume and has not a definite shape

- A gas has not a definite volume and has not a definite shape

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- A solid has a definite volume and has a definite shape

- A liquid has a definite volume and has not a definite shape

- A gas has not a definite volume and has not a definite shape

8 0
1 year ago
What mass of barium sulfate (233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of
Rzqust [24]

Answer:

4.37 g of barium sulphate

Explanation:

The reaction equation is;

3BaCl2(aq) + Fe2(SO4)3(aq) ---->3 BaSO4(s) + 2FeCl3(aq)

From the question, the number of moles of both barium chloride and FeSO4 = 125/1000 L × 0.150 M = 0.01875 moles

To find the limiting reactant;

3 moles of barium chloride yields 3 moles of barium sulphate

0.01875 moles of barium chloride yields 3 × 0.01875 moles/3 = 0.01875 moles of barium sulphate

1 mole of iron III sulphate yields 3 moles of barium sulphate

0.01875 molesof iron III sulphate yields 0.01875 moles ×3/1 = 0.05625 moles of barium sulphate

Hence,barium chloride is the limiting reactant

Amount of barium sulphate produced = 0.01875 moles × 233 g/mol = 4.37 g of barium sulphate

4 0
3 years ago
Need help ASAP !!
Kitty [74]

Answer:

it's a segment

Explanation:

it has multiple end points

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