Answer:
Please find the ten balanced equations below
Explanation:
According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:
1. C + O2 → CO2 (balanced)
2. 2H2 + O2 → 2H2O (balanced)
3. 2Na + 2H2O → 2NaOH + H2 (balanced)
4. 4Na + O2 → 2Na2O (balanced)
5. 2Na + Cl2 → 2NaCl (balanced)
6. NaOH + HCl → NaCl + H2O (balanced)
7. NaOH + HNO3 → NaNO3 + H2O (balanced)
8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)
9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)
10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)
Answer:
I don't know
Explanation:
I'm sorry I didn't learn this in my life,I have never reach in this level
Answer:
a) 0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b) 0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c) Instantaneous rate of the reaction at t=800 s :
Instantaneous rate :
Explanation:
Average rate of the reaction is given as;
a.) The average reaction rate between 0.0 s and 1500.0 s:
At 0.0 seconds the concentration was =
At 1500.0 seconds the concentration was =
0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b.) The average reaction rate between 200.0 s and 1200.0 s:
At 0.0 seconds the concentration was =
At 1500.0 seconds the concentration was =
0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c.) Instantaneous rate of the reaction at t=800 s :
At 800 seconds the concentration was =
Instantaneous rate :
Answer:
Using the smallest coefficient the chemical equation is written as
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)
Explanation:
Neutralization reaction is a reaction in which acid and base reacts quantitatively to form salt and water.
Base = potassium hydroxide
acid = phosphoric acid.
KOH =potassium hydroxide
H3PO4 = Phosphoric acid
KOH(aq) + H3PO4(aq) → K3PO4(aq) + H2O(aq)
The number of atoms on both side (reactant and product) of the equation are not equal so, we need to balance it.
3KOH(aq) + H3PO4(aq) → K3PO4(aq) + 3H2O(aq)
The product are salt and water.
Salt = K3PO4
water = H2O
The equation is balanced on both sides .
The potassium atom is 3 on both sides , oxygen atom is 7 on both sides, hydrogen atom is 6 on both sides and phosphorus atom is 1 on both sides.
The first one is the correct choice. We have that bases have [H+] lower than that of water since the product of H+ and OH- concentration in water is constant; in acids H+ are more than OH-, in bases H+ are less than OH- and in neutral PH (water) H+=OH- ; hence in bases OH->H+ . We have that strong bases and strong acids dissociate completely in water (by definition), their pHs are as much far from the middle of the pH scale (7) as possible (around 0 for acids or 14 for bases) and they corrode metals due to how drastic they are.