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denis23 [38]
3 years ago
12

Thermal energy would naturally flow between objects at which temperatures?

Chemistry
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

i think the answer is letter C. From 35°c to 45°c

Explanation:

sorry if it is wrong

You might be interested in
SOMEONE PLS HELP ASAP!!
Oksi-84 [34.3K]

Answer:

Two cinder blocks 6 centimeters apart

Explanation:

im not 100% certain but the 2 cinder blocks are more dense than the other options

sry if its wrong

5 0
3 years ago
A container is filled with a gas. The container has a wall controlled by a moveable piston. The
ioda

Answer:

The new volume will be 3.67 L.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P*V=k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case:

  • P1= 1.85 atm
  • V1= 4.64 L
  • P2= 2.34 atm
  • V2= ?

Replacing:

1.85 atm* 4.64 L= 2.34 atm* V2

Solving:

V2= \frac{1.85 atm* 4.64 L}{2.34 atm}

V2= 3.67 L

<u><em>The new volume will be 3.67 L.</em></u>

6 0
3 years ago
Rank the following solutions from lowest to highest vapor pressure.
Fantom [35]

Solution :

When non volatile solute is added to solvent, vapor pressure gets lowered.

Relative lowering in vapor pressure is given :

$\frac{P^0-P}{P^0}$   = $\text{mole fraction}$ of solute

$\frac{P^0-P}{P^0}=x_B$

$P^0$ = vapor pressure of pure solvent

P = vapor pressure of solution

$x_B$ = mole fraction of solute

$x_B=\frac{n_B}{n_A+n_B}$

$n_B $ = $\text{number of moles of solute}$

$n_A$ = $\text{number of moles of solvent}$

Number of moles $=\frac{\text{weight}}{\text{molecular weight}}$

$\frac{P^0-P}{P^0}=\frac{w_B/M_B}{w_A/M_A+w_B/M_B}$

            $\approx \frac{w_B/M_B}{w_A/M_A}$

1. For 10 g of $CH_3COOK$

         $CH_3COOK \rightarrow CH_3COO^- + K^+$

  Ions = 2

It will affect colligative property.

$\frac{P^0-P}{P^0} = \frac{i \times 10/98}{w_A/M_A}$

Relative lowering in vapor pressure will be :

$=\frac{2 \times 10/98}{w_A/M_A}$

$=\frac{0.20}{w_A/M_A}$

2. For 20 g sucrose

Sucrose is non electrolyte, i = 1

$\frac{P^0-P}{P^0} = \frac{ 20/342}{w_A/M_A}$

            $=\frac{0.050}{w_A/M_A}$

3. For 20 g of glucose.

   Glucose is a non electrolyte, i = 1

   $\frac{P^0-P}{P^0} = \frac{20/180}{w_A/M_A}$

               $=\frac{0.11}{w_A/M_A}$

$w_A/M_A$ is same in all three solutions.

Hence, lowering in vapor pressure is maximum in $CH_3COOK$ and minimum is Sucrose.

Vapor pressure from lowest to highest.

10 g of $CH_3COOK$ < 20 g of glucose < 20 g of sucrose

               

6 0
3 years ago
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together
Darina [25.2K]

Answer:

a. molecules that gain or lose an atom to develop a bonding charge

Explanation:

6 0
3 years ago
10)Calculate the molarity of a potassium dichromate solution prepared by placing 9.67 g of K Cro in a
lbvjy [14]

Answer:

0.33 M

Explanation:

From the question given above, the following data were obtained:

Mass of K₂Cr₂O₇ = 9.67 g

Volume of solution = 100 mL

Molarity =?

Next, we shall determine the number of mole in 9.67 g of K₂Cr₂O₇. This can be obtained as follow:

Molar mass of K₂Cr₂O₇ = (39×2) + (52×2) + (16×7)

= 78 + 104 + 112

= 294 g/mol

Mass of K₂Cr₂O₇ = 9.67 g

Mole of K₂Cr₂O₇ =?

Mole = mass /Molar mass

Mole of K₂Cr₂O₇ = 9.67 / 294

Mole of K₂Cr₂O₇ = 0.033 mole

Next, we shall convert 100 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

100 mL = 100 mL × 1 L / 1000 mL

100 mL = 0.1 L

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of K₂Cr₂O₇ = 0.033 mole

Volume of solution = 0.1 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.033 / 0.1

Molarity = 0.33 M

Thus, the molarity of the solution is 0.33 M

8 0
3 years ago
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