Answer:
Two cinder blocks 6 centimeters apart
Explanation:
im not 100% certain but the 2 cinder blocks are more dense than the other options
sry if its wrong
Answer:
The new volume will be 3.67 L.
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
P*V=k
Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1 * V1 = P2 * V2
In this case:
- P1= 1.85 atm
- V1= 4.64 L
- P2= 2.34 atm
- V2= ?
Replacing:
1.85 atm* 4.64 L= 2.34 atm* V2
Solving:

V2= 3.67 L
<u><em>The new volume will be 3.67 L.</em></u>
Solution :
When non volatile solute is added to solvent, vapor pressure gets lowered.
Relative lowering in vapor pressure is given :
=
of solute

= vapor pressure of pure solvent
P = vapor pressure of solution
= mole fraction of solute

= 
= 
Number of moles 


1. For 10 g of 

Ions = 2
It will affect colligative property.

Relative lowering in vapor pressure will be :


2. For 20 g sucrose
Sucrose is non electrolyte, i = 1


3. For 20 g of glucose.
Glucose is a non electrolyte, i = 1


is same in all three solutions.
Hence, lowering in vapor pressure is maximum in
and minimum is Sucrose.
Vapor pressure from lowest to highest.
10 g of
< 20 g of glucose < 20 g of sucrose
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
Answer:
0.33 M
Explanation:
From the question given above, the following data were obtained:
Mass of K₂Cr₂O₇ = 9.67 g
Volume of solution = 100 mL
Molarity =?
Next, we shall determine the number of mole in 9.67 g of K₂Cr₂O₇. This can be obtained as follow:
Molar mass of K₂Cr₂O₇ = (39×2) + (52×2) + (16×7)
= 78 + 104 + 112
= 294 g/mol
Mass of K₂Cr₂O₇ = 9.67 g
Mole of K₂Cr₂O₇ =?
Mole = mass /Molar mass
Mole of K₂Cr₂O₇ = 9.67 / 294
Mole of K₂Cr₂O₇ = 0.033 mole
Next, we shall convert 100 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
100 mL = 100 mL × 1 L / 1000 mL
100 mL = 0.1 L
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of K₂Cr₂O₇ = 0.033 mole
Volume of solution = 0.1 L
Molarity =?
Molarity = mole / Volume
Molarity = 0.033 / 0.1
Molarity = 0.33 M
Thus, the molarity of the solution is 0.33 M