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Schach [20]
3 years ago
12

6. Write a balanced equation for each reaction. You must change each word equation into a chemical equation with actual formulas

of the substances. Include the physical states of all substances in the reactions:
 (a) Combustion reaction of butane (C4H10) that produces carbon monoxide and steam.

 (b) Reaction of Ammonium phosphate solution with Potassium hydroxide solution yields Potassium phosphate solution + water + ammonia gas

Chemistry
1 answer:
leva [86]3 years ago
4 0
The answer is in the pic!

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What is the major organic product obtained from the following reaction?
trapecia [35]

The correct option is (b)

NaNH2 is an effective base. It can be a good nucleophile in the few situations where its strong basicity does not have negative side effects. It is employed in elimination reactions as well as the deprotonation of weak acids.Alkynes, alcohols, and a variety of other functional groups with acidic protons, such as esters and ketones, will all be deprotonated by NaNH2, a powerful base.Alkynes are deprotonated with NaNH2 to produce what are known as "acetylide" ions. These ions are powerful nucleophiles that can react with alkyl halides to create carbon-carbon bonds and add to carbonyls in an addition reaction.Acid/base and nucleophilic substitution are the two types of reactions.Using the right base, terminal alkynes can be deprotonated to produce a carbanion.A good C is the acetylide carbanion.The acetylide carbanion can undergo nucleophilic substitution reactions because it is a potent C nucleophile. (often SN2) with 1 or 2 alkyl halides with electrophilic C to create an internal alkyne (Cl, Br, or I).Elimination is more likely to occur with 3-alkyl halides.It is possible to swap either one or both of the terminal H atoms in ethylene (acetylene) to create monosubstituted (R-C-C-H) and symmetrical (R = R') or unsymmetrical (R not equal to R') disubstituted alkynes (R-C-C-R').

Learn more about NANH2 here :-

brainly.com/question/12601787

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7 0
2 years ago
Revolver features several firing chambers located within...
Blizzard [7]

Answer:

What are the characteristics of a revolver?

Explanation:

The revolver features several firing chambers located within a revolving cylinder. The cylinder rotates as the revolver is fired, lining up each bullet mechanically.

8 0
2 years ago
¿Un kilo y medio a cuantos gramos equivale?
Anastaziya [24]

Answer:

Por tanto, podemos concluir que en medio kilogramo hay un total de 500 gramos

7 0
2 years ago
A parachute on a racing dragster opens and changes the speed of the car from 85 m/s to 45 m/s in a period of 4.5 seconds. What i
LiRa [457]

Answer:

- 8.89 m/s^{2}

Explanation:

\frac{(Vf-Vo)}{time} =  \frac{(45-85 m/s)}{4.5s} = - 8.89 m/s^{2}

7 0
3 years ago
Read 2 more answers
What is the empirical formula of a compound with a % composition of 40.1% sulfur and 59.9% oxygen?
olga_2 [115]

Answer:

The empirical formula is SO

Explanation:

The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound.

Given 40.1% Sulphur and 59.9% oxygen.

We have to assume the mass of the compound to make our calculations easy.

Let's assume that the mass of the compound is 100g, that the mass of sulphur will be 40.1g and the mass of oxygen will then be 59.9g.

Number of moles= reacting mass/ molar mass

Molar mass of Sulphur = 32g/mol

Molar mass of Oxygen = 16g/mol

No of moles of S= 40.1g/100g

=0.401 moles of S

No of moles of O = 59.9g/100g

=0.599 moles of O

•These are the relative mole ratios for the compound,

•They need to be converted from decimals into whole numbers

•Turn mole ratio into whole number ratio by dividing by all the elements by the least/smallest number of moles calculated.

Number of moles of S = 0.401moles/0.401 = 1 mol S

Number of moles of O = 0.599moles/0.401 = 1.49 mol O which is approximately 1 (to the nearest whole number, considering it tenths' value which is 4 and less than 5)

The empirical formula is therefore SO.

4 0
3 years ago
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