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Bingel [31]
3 years ago
13

The physical phenomenon that MRI is based on does not depend on ionizing radiation, but on other properties of atoms instead. Wh

at is this phenomenon called?
gamma-ray bursts
positron emission
X-ray propagation
nuclear magnetic resonance
Physics
2 answers:
love history [14]3 years ago
5 0

nuclear magnetic resonance

hammer [34]3 years ago
4 0

This phenomenon is called Nuclear Magnetic Resonance.

When I met my future wife, she was working in the medical research building next door to the communications building where I worked. (We shared a parking lot.) MRI was not a thing yet, and she was doing research in Nuclear Magnetic Resonance. I learned a lot about it when I walked next door to visit her in her lab. Strange as it may seem, several years earlier, her older brother was involved in the invention of the CAT scan. When we got married, I figured that our kids had at least a 50% chance of inheriting some brains. So we had some, and they've done OK.

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Charge is measured in coulombs.

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Measurements of two electric currents are shown in the chart. A 3-column table with 2 rows titled Electric Currents. The first c
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As in Problem A above, a block of mass M starts from rest and is pushed up a frictionless ramp inclined at an angle θ above the
Tasya [4]

Answer:

A(i)

The solution to this question is shown on the second uploaded image

A(ii)

The final speed is v = \sqrt{2L (\frac{F}{M} - gsin\theta )}

B

The block speed after a distance L  is  v= \sqrt{2L (\frac{F}{M} -gsin \theta )}

Explanation:

From the question  

The net force i the x-direction is mathematically represented as

               F_{net} = Ma

From the the diagram in the second uploaded image we see that

             F_{net} = F - Mgsin \theta

Therefore

              F- Mgsin\theta = Ma

Making a the subject

              a = \frac{F}{M} - gsin\theta

Applying the law of motion

                v^2 =u^2 + 2as

where  u = 0 m/s and s =L

       v^2 = 0 + 2(\frac{F}{M} - gsin \theta )L

=>   v = \sqrt{2L (\frac{F}{M} - gsin\theta )}

According to Energy conservation law and work theorem

           Workdone by F + Workdone by gravity = change in kinetic energy

Mathematically this is given as

                F * L - (mgsin \theta)L = \frac{1}{2} M (v^2-u^2)

   Since u = 0 m/s

                    L (\frac{F}{M} - gsin \theta ) = \frac{1}{2} v^2

                  v= \sqrt{2L (\frac{F}{M} -gsin \theta )}

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Answer:

i think the color

I THINK

Explanation:

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