Question

What is the equivalent resistance of a circuit that contains three 10.0  resistors connected in series to a 6.0 V battery

Answer 1

Answer:

30 ohms

Explanation:

Answer 2

The equivalent resistance of n resistors in series is given by:
$R_{eq} = R_1 + R_2 + ... + R_n$
In our circuit, we have three resistors of $10.0 \Omega$ each, therefore the equivalent resistance of the circuit is
$R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 10.0 \Omega + 10.0 \Omega =30.0 \Omega$