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Molodets [167]
3 years ago
6

What is the equivalent resistance of a circuit that contains three 10.0  resistors connected in series to a 6.0 V battery

Physics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

30 ohms

Explanation:

disa [49]3 years ago
4 0
The equivalent resistance of n resistors in series is given by:
R_{eq} = R_1 + R_2 + ... + R_n
In our circuit, we have three resistors of 10.0 \Omega each, therefore the equivalent resistance of the circuit is
R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 10.0 \Omega + 10.0 \Omega =30.0 \Omega
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By definition we have that the energy at the top of the ramp is equal to the energy at the bottom of the ramp. This is due to the principle of energy conservation.

We have then:

E1 = E2

The energy at the top is only potential energy:

E1 = mgh

Where,

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The energy when it falls is transformed into kinetic energy and therefore:

E2 = \frac {1} {2} mv ^ 2

Where,

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Therefore we have:

mgh = \frac {1} {2} mv ^ 2

Answer:

The potential energy is transformed into kinetic energy.

mgh = \frac {1} {2} mv ^ 2

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