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Molodets [167]
3 years ago
6

What is the equivalent resistance of a circuit that contains three 10.0  resistors connected in series to a 6.0 V battery

Physics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

30 ohms

Explanation:

disa [49]3 years ago
4 0
The equivalent resistance of n resistors in series is given by:
R_{eq} = R_1 + R_2 + ... + R_n
In our circuit, we have three resistors of 10.0 \Omega each, therefore the equivalent resistance of the circuit is
R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 10.0 \Omega + 10.0 \Omega =30.0 \Omega
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Read 2 more answers
A 2,700-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the colli
Leto [7]

Answer:

6200 J

Explanation:

Momentum is conserved.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

The car is initially stationary.  The truck and car stick together after the collision, so they have the same final velocity.  Therefore:

m₁ u₁ = (m₁ + m₂) v

Solving for the truck's initial velocity:

(2700 kg) u = (2700 kg + 1000 kg) (3 m/s)

u = 4.11 m/s

The change in kinetic energy is therefore:

ΔKE = ½ (m₁ + m₂) v² − ½ m₁ u²

ΔKE = ½ (2700 kg + 1000 kg) (3 m/s)² − ½ (2700 kg) (4.11 m/s)²

ΔKE = -6200 J

6200 J of kinetic energy is "lost".

3 0
3 years ago
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