Answer:
3.50*10^-11 mol3 dm-9
Explanation:
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.
Ag2C2O4 --> 2Ag+ + C2O4 2-
So Ksp = [Ag+]^2 * [C2O42-]
In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.
So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)
= 3.50*10^-11 mol3 dm-9
Answer:
240.5g
Explanation:
steps:
given/ 1 - 2.5mol LiBr / 1
Multiplication - 78g/ 1 mol ( 78 comes from the formula weight of LiBr )
answer- 240.5g
Answer:
Explanation:
Ratio of C : H : N : O in grams
= 72.15 : 7.08 : 4.68 : 16.03 in grams
Ratio of C : H : N : O in moles
72.15/12 : 7.08/1 : 4.68/14 : 16.03/16 in moles
6.01 : 7.08 : .334 : 1.00
6.01/ .334 : 7.08/.334 : .334/.334 : 1.00/.334 in moles
18 : 21.19 : 1 : 3
18 : 21 : 1 : 3
empirical formula = C₁₈H₂₁NO₃
It is codeine .
Answer:
A. The number of moles of HNO2 will remain the same. True
B. The number of moles of NO2- will remain the same. False
C. The equilibrium concentration of H3O will remain the same. False
D. The pH will decrease. False
E. The ratio of [HNO2] / [NO2-] will remain the same. True
Explanation:
The mixture of nitrous acid and potassium nitrite is a buffer solution. Hence the properties outlined above. Buffer solutions are designed to militate against changes in acidity or alkalinity. This explains why the above statements were categorized as true or false accordingly.
