Answer: 143.66 grams of M (g) is contained in 396 g of the mineral
Explanation:
Given : mineral contains metal M and sulphur
Mass of mineral = 4.3 g
Mass of metal M in mineral = 1.56 g
Thus if 4.3 gram of mineral contains metal = 1.56 g
Using unitary method for solving this :
1 g of mineral contains metal =
396 g of mineral contains metal =
Thus 143.66 grams of M (g) is contained in 396 g of the mineral
Answer:
c 0.40 L
Explanation:
Calculate by using Boyle's Law P₁V₁=P₂V₂
(0.14atm)(2.4L) = (0.84atm)(V₂)
0.336 atmL = (0.84atm)(V₂)
V₂ = 0.336 atmL/0.84atm
V₂ = 0.4 L
<u>Answer:</u> There are
ammonium ions and
sulfate ions in the given amount of ammonium sulfate.
<u>Explanation:</u>
We are given 0.270 moles of ammonium sulfate and we need to find the number of ammonium and sulfate ions in it. The equation for the ionization of ammonium sulfate is given by the reaction:

By Stoichiometry,
1 mole of ammonium ions dissociates into 2 moles of ammonium ions and 1 mole of sulfate ion.
According to the mole concept:
1 mole of an ionic compound contains
number of ions.
Hence, 0.270 mole of ammonium sulfate will contain
number of ammonium ions and
number of sulfate ions.
Hence, there are
ammonium ions and
sulfate ions in the given amount of ammonium sulfate.
Answer:
One molecule of water has two hydrogen atoms covalently bonded to a single oxygen atom. Water is a tasteless, odorless liquid at ambient temperature and pressure.
Explanation:
Hope this helps :) Have a great day!