We are given the following:
thickness, T = 0.155 mm
charge-carrier density, n = 1.05 x 10^25 / m3
current, I = 2.67 A
voltage, V = 4.89 mV
We are asked to get the magnetic strength, B
To solve this, we use the Hall Effect formula:
V = - IB / neT
where e is the charge of an electron which is e = 1.60 x 10^-19 and B is the magnetic field
Rearranging the formula
B = -V n e T / I
Substituting the given values
B = - (4.89 x 10^-3 V) (1.05 x 10^25 / m3) (0.155 x 10^-3 m) / 2.67 A
B = -2.98 x 10^18 Teslas
<h2>
Height of cliff is 66.43 meter.</h2>
Explanation:
Consider the horizontal motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 1770 m/s
Acceleration, a = 0 m/s²
Displacement, s = 6520 m
Substituting
s = ut + 0.5 at²
6520 = 1770 x t + 0.5 x 0 xt²
t = 3.68 s
Time of flight of shell = 3.68 s.
Now consider the vertical motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3.68 s
Substituting
s = ut + 0.5 at²
s = 0 x 3.68 + 0.5 x 9.81 x 3.68²
s = 66.43 m
Height of cliff is 66.43 meter.
Answer:
The speed of the plank is 81.68 m/s
Explanation:
Given that,
Speed of bullet = 152 m/s
Speed of wood = 128 m/s
Speed of another bullet = 97 m/s
We need to calculate the speed of plank
Using conservation of momentum
Where,
u = initial velocity
v = final velocity
....(I)
....(II)
From equation(I) and equation(II)
Hence, The speed of the plank is 81.68 m/s
Explanation:
1) reduction in current
2)less no. of coils per unit length
3) removal of soft iron core
