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Rzqust [24]
3 years ago
14

An airplanes flies 2220 miles in 3. What is it’s average speed in miles per hour?

Physics
2 answers:
Arisa [49]3 years ago
7 0

Distance = (Rate)(Time), so Time = Distance/Rate

= (2220 miles)/(555 mi/hr) = 4 hours

Aleksandr-060686 [28]3 years ago
5 0
It is traveling at 740 mph
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If forces acting on an object are unbalanced, which factor may result from an unbalanced force? A.The net force is negative. B.T
bezimeni [28]

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<h2>A. The net force is negative.</h2>

Explanation:

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umka2103 [35]

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A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

Q_B=9\times10^-6C

d_A = 1+x cm

d_B=x cm

k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

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1 year ago
Four students made a graphic organizer describing the parts of the atom.
Nikitich [7]

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3 years ago
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A wheel of mass 4kg is pulled up a plane inclined at 30° to the horizontal by a force of 45N applied to the axle and parallel to
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Answer:

v = 10 m/s

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Work done on the wheel

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Some is converted to potential energy

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As there is no friction mentioned, the remainder is kinetic energy

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ω = v/R

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v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6

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