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Zinaida [17]
3 years ago
14

On Earth, Yancy hits a golf ball as hard as he can. The golf ball flies 150 meters before hitting the ground. About how far woul

d the golf ball fly if Yancy hit it on the surface of Mercury with exactly the same amount of force and in the same direction? (Ignore the air resistance on both planets.) A. 150 yards B. more than 150 meters C. 150 meters D. less than 150 meters
Physics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

More than 150 meters

Explanation:

Vitek1552 [10]3 years ago
4 0

Answer:

more than 150 meters

Explanation:

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ella [17]

Answer:

\frac{dR(t)}{dt}=0.06\Omega

Explanation:

Since R(t)=\frac{V}{I(t)}, we calculate the resistance rate by deriving this formula with respect to time:

\frac{dR(t)}{dt}=\frac{d}{dt}(\frac{V}{I(t)})=V\frac{d}{dt}(\frac{1}{I(t)})

Deriving what is left (remember that (\frac{1}{f(x)})'=-\frac{1}{f(x)^2}f'(x)):

\frac{d}{dt}(\frac{1}{I(t)})=-\frac{1}{I(t)^2}\frac{dI(t)}{dt}

So we have:

\frac{dR(t)}{dt}=-\frac{V}{I(t)^2}\frac{dI(t)}{dt}

Which for our values is (the rate of <em>I(t)</em> is decreasing so we put a negative sign):

\frac{dR(t)}{dt}=-\frac{24V}{(56A)^2}(-8A/s)=0.06\Omega

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3 years ago
Question 11 of 11
VladimirAG [237]

Answer:

D.

Explanation:

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with
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(D) The gravitational force between the astronaut and the asteroid.

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Weight on planet Mars ​
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If you weigh 150 pounds (68 kg.) on Earth, you would weigh 57 lbs. (26 kg.) on Mars

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If the ground is flat, and both bullets are released at the same time from the same height, then they both hit the ground at the same time.

The horizontal motion of the one from the gun has no effect on its vertical motion.

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