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lakkis [162]
2 years ago
6

An apple contains 165 Calories. How many actual calories does it contain? How many joules does it contain

Physics
1 answer:
jasenka [17]2 years ago
8 0

Answer:

95 calories

Explanation:

A medium-sized apple has only 95 calories but plenty of water and fiber.

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Why it is easier to remove a 2p electron from an oxygen atom than from a nitrogen atom?
DedPeter [7]

Answer:

The electrons in oxygen are paired while in nitrogen, they are not.

Explanation:

To analyse this we start with writing out the ground state electronic configurations for both elements.

Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons                  ↑↓   ↑   ↑

Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons  ↑    ↑    ↑

Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied

7 0
3 years ago
Which best describes what happens when light traveling through air enters water at an angle?
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I think it is "A'' 'It moves along straight lines in air and changes direction when it enters water.
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3 years ago
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you throw a rock with a horizontal velocity at 36.6 m/s out a window that is 29.5 m above the ground. What was it’s total time i
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29.5-4.9x^2= your answer
4 0
3 years ago
A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
masha68 [24]

Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

  • original frequency of the source, f=1200\ Hz
  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

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3 years ago
A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the
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Used an app called Mephyso to do the calculation.

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