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3 years ago

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The 360-turn primary coil of a step-down transformer is connected to an ac line that is 120 V (rms). The secondary coil is to su

pply 15.0 A at 6.30 V (rms). 1) Assuming no power loss in the transformer, calculate the number of turns in the secondary coil. (Express your answer to two significant figures.)

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer:

N₂ = 19 turns

Explanation:

A transform is a system with two different windings where the variation of the magnetic beam is the same, if there are no losses in the system we can use Faraday's law

V₁ = -N₁ $\frac{d \Phi_B }{dt}$

v₂ = - N₂ \frac{d \Phi_B }{dt}

$\frac{V_1}{N_1} = \frac{V_2}{N_2}$

in this case we look for the number of turns in the second winding

N₂2 = $N_1 \ \frac{ V_2}{V_1}$

calculate us

N₂ = 360 6.30/ 120

N₂ = 18.9 turn

The number of turns must be an integer

N₂ = 19 turns

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So, the number of photons required to heat the water is the total energy absorbed by the water divided by the energy of a single photon:
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What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 7400 N

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Answer: a = 1.32 * 10^18m/s² due north

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The force exerted on the charge by the electric field of intensity (E) is given by

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Thus

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Where a = acceleration of charge

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3 years ago

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Answer:

a)

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a)

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b)

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Answer:

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${F_{\rm{f}}} = {\mu _{\rm{s}}}{m_1}g$

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Substitute for , [/tex]{m_1}[/tex] for in the equation .

${F_{\rm{f}}} = {m_1}a$

Substitute ${\mu _{\rm{s}}}{m_1}g$ for ${F_{\rm{f}}}$ in the equation ${F_{\rm{f}}} = {m_1}a$

${\mu _{\rm{s}}}{m_1}g = {m_1}a$

Rearrange for a.

$a = {\mu _{\rm{s}}}g$

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Substitute for for in the equation .

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Substitute for in the above equation .

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5 0

3 years ago