The 360-turn primary coil of a step-down transformer is connected to an ac line that is 120 V (rms). The secondary coil is to su
1 answer:
Answer:
N₂ = 19 turns
Explanation:
A transform is a system with two different windings where the variation of the magnetic beam is the same, if there are no losses in the system we can use Faraday's law
V₁ = -N₁
v₂ = - N₂ \frac{d \Phi_B }{dt}
in this case we look for the number of turns in the second winding
N₂2 =
calculate us
N₂ = 360 6.30/ 120
N₂ = 18.9 turn
The number of turns must be an integer
N₂ = 19 turns
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Answer:
a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.
b) The final speed of the block of ice is 9.8 meters per second.
Explanation:
a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.
The weight of the block (), measured in newtons, is:
(1)
Where:
- Mass of the block of ice, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
If we know that and
, the magnitudes of the weight and normal force of the block of ice are, respectively:
And the pull force is:
The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.
b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:
(2)
Where:
,
- Initial and final speeds of the block, measured in meters per second.
- Horizontal net force, measured in newtons.
- Impact time, measured in seconds.
Now we clear the final speed in (2):
If we know that ,
,
and
, then final speed of the ice block is:
The final speed of the block of ice is 9.8 meters per second.