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3 years ago

What are the roots of the quadratic function in the graph?

Mathematics

2 answers:

RideAnS [48]3 years ago

7 0

Answer:

Step-by-step explanation:

The roots are the points on the x- axis where the function has a value of zero. That is where the graph crosses the x- axis

The graph crosses the x- axis at x = - 3 and x = 4, hence

Roots of the quadratic function are x = -3, 4 → D

qwelly [4]3 years ago

5 0

Answer:

Step-by-step explanation:

The roots are where the curve crosses the x-axis. So that's x=-3 and x=4.

Answer D.

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Find the limit<br> Picture below

pogonyaev

Answer:

a. 4

Step-by-step explanation:

We want to find;

$\lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

If $f(x)=x^2$ .

$f(2+h)=(2+h)^2$

$f(2+h)=4+4h+h^2$

Also;

$f(2)=2^2$

$f(2)=4$

This implies that;

$\lim_{h \to 0} \frac{4+4h+h^2-4}{h}$

Simplify;

$\lim_{h \to 0} \frac{4h+h^2}{h}$

Factor to get;

$\lim_{h \to 0} \frac{h(4+h)}{h}$

Cancel the common factors.

$\lim_{h \to 0} 4+h$

Substitute h=0 to get

$\lim_{h \to 0} 4+h=4+0=4$

7 0

4 years ago

Read 2 more answers

for one history test,peter has to answer 15 questions. of these questions, peter answered 60% of them correctly. how many questi

RoseWind [281]

Peter answered 9 of the questions correctly. 15 divided by 100 to get .15 and then multiply by 60 to get 9. Got 9 correct, 7 incorrect.

5 0

4 years ago

John randomly picks a number from 1 to 5 (both inclusive) and a letter from A to E (both inclusive). What is the probability tha

Greeley [361]

Answer:

$P(A \cap B) = P(A) *P(B) =\frac{1}{5} \frac{1}{5}= \frac{1}{25}$

So then the best option would be:

a. 1/25

Step-by-step explanation:

For this case we assume that the sample space for the numbers is :

$S_1= [A,B,C,D,E]$

And the sample space for the numbers is:

$S_2 =[1,2,3,4,5]$

Both sampling spaces with a size of 5.

We define the following events:

A="We select a 2 from the numbers"

B= "We select a E from the letters"

We can find the individual probabilities for each event like this:

$P(A)= \frac{1}{5}$

$P(B) = \frac{1}{5}$

And assuming independence we can find the probability required like this:

$P(A \cap B) = P(A) *P(B) =\frac{1}{5} \frac{1}{5}= \frac{1}{25}$

The last probability is the probability of obtain obtain a 2 AND an E

So then the best option would be:

a. 1/25

3 0

4 years ago

Read 2 more answers

HELP ME!!!!!!!!!The potatoes beth brought weighed 3 kilograms and 420 grams. Her onions weighed 1,050 grams less than the potato

Volgvan

I think 306? Not completely sure! Hope this helps!!

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3 years ago

Use the distributive property to find an expression that is equivalent to 27x2(second power)-42x+12

Lina20 [59]

27x^2 - 42x + 12

3 is a common factor:-

= 3(9x^2 - 14x + 4)

That is the equivalent expression.

5 0

3 years ago