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DaniilM [7]
3 years ago
5

A capacitor consists of two concentric cylinders. The inner cylinder has a radius of 0.001 m and the outer cylinder a radius of

0.0011 m. The length of the capacitor is 1 m. If centered on the z-axis, the region 0 < ∅ < π has a dielectric constant of 2 and the region π < ∅ < 2π a dielectric constant of 4. Find the capacitance. Ignore fringing fields.
Physics
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

The capacitance is 1.75 nF

Explanation:

From the question we are given that

    The inner radius is r_{in}  = 0.001

     The outer radius is r_{out} = 0.0011 \ m

    Length of the capacitor is L = 1m

    The dielectric constant is Di = 2 \ for  \ 0 < \phi < \pi

   The dielectric constant is  Di_2  = 4 \ for \ \pi < \phi < 2\pi

Generally the capacitance of a capacitor can be mathematically represented as

                C = \frac{\pi \epsilon_0 Di_1 L}{ln\frac{r_{out}}{r_{in}} } + \frac{\pi \epsilon_0 Di_2L}{ln\frac{r_{out}}{r_{in}} }

                   = \frac{\pi \epsilon_0 L (Di_1 + Di_2)}{ln\frac{r_{out}}{r_{in}} }

                  = \frac{(3.142)(8.85*10^{-12})(1)(2+4)}{ln\frac{0.0011}{0.001} }

                  =1.75*10^{-9} F

                  1.75nF

                 

                   

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Explanation:

Expression for time period of a pendulum is as follows

T = 2\pi\sqrt{\frac{l}{g} }

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1.583 = 2\pi\sqrt{\frac{l}{9.846} }

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8 0
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If the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules _______, the average
VLD [36.1K]

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Explanation:

If the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules increases, the average force of an individual collision increases, and the average number of collisions with the wall, per unit area, per second increases.

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Read 2 more answers
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GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

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Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

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And

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Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

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