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Aleks04 [339]
3 years ago
13

A NATO base in northern Norway is warmed with a heat pump that uses 7.0 °C ocean water as the cold reservoir. Heat extracted fro

m the ocean water warms fluid to 80°C; this warmed fluid is used to heat the building. When the system is working at full capacity, 2,000 kW of heat is delivered to the building at the cost of 600 kW of electric energy. a. What is the actual coefficient of performance of the system? b. What is the theoretical maximum coefficient of performance of the system?
Physics
1 answer:
tatiyna3 years ago
3 0

Answer:

3.33, 4.84

Explanation:

A) Actual coefficient of performance can be calculated by the formula stated below

Actual COP = heat delivered/ work required

Actual COP = 2,000/600

Actual COP = 3.33

B) Th = High temperature = 80°C + 273 = 353K

Tl = Low temperature = 7°C + 273 = 280K

The theoretical maximum coefficient of performance can ve calculated by the formula

Theoretical COP = Th/(Th-Tl)

Theoretical COP = 353/(353-280)

Theoretical COP = 353/73

Theoretical COP = 4.84

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The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on
lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied (\Delta t):

I=F\Delta t

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

\Delta p = m \Delta v

where m is the mass and \Delta v is the change in velocity. Multiplying and dividing by \Delta t, we get

\Delta p = m \frac{\Delta v}{\Delta t} \Delta t

and since \frac{\Delta v}{\Delta t} is equal to the acceleration, a, we have

\Delta p = ma \Delta t

And since the product (ma) is equal to the force, we have

\Delta p = F \Delta t

which corresponds to the impulse.

5 0
3 years ago
Which of the following measurements has two significant digits?
myrzilka [38]
0.022 has 2 digits because you would count from the left starting with the first nonzero number
7 0
3 years ago
Read 2 more answers
If both mass and speed are doubled, what happens to its momentum?
puteri [66]

The general formula is:      Momentum = (mass) x (speed)

I never like to just write a bunch of algebra without explaining it.
But in this particular case, there's really not much to say, and
I think the algebra will pretty well explain itself.  I hope so:


Original momentum = (original mass) x (original speed)


New momentum = (2 x original mass) x (2 x original speed)

                           = (2) x (original mass) x (2) x (original speed)

                           = (2) x (2) x (original mass) x (original speed)

                           =  (4) x (original mass) x (original speed)

                           =  (4) x (original momentum).

7 0
3 years ago
A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
balandron [24]

Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

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<span>Note that when you back off, you back off by and large yet can locally in time quicken a tiny bit, suppose amid 1/tenth of a sec since you achieved a segment of the street which was slanting. In any case, this does not change the way that when the speed diminishes, the quickening is negative.</span>
4 0
3 years ago
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