Answer:
The mole fraction of N₂ is 0.26.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.
So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:
PA = XA * PT
In this case:
- PA= PN₂= 300 torr
- XA=XN₂= ?
- PT= 1.50 atm= 1140 torr (being 1 atm= 760 torr)
Replacing:
300 torr= XN₂*1140 torr
Solving:

XN₂= 0.26
<u><em>The mole fraction of N₂ is 0.26.</em></u>
HEY DEAR..
<u>PHYSICAL</u><u> </u><u>CHANGE</u>
<em>Those</em><em> </em><em>Changes</em><em> </em><em>in</em><em> </em><em>which</em><em> </em><em>no</em><em> </em><em>new</em><em> </em><em>substances</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>are</em><em> </em><em>called</em><em> </em><em>physical</em><em> </em><em>changes</em><em>.</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>temporary</em><em> </em><em>changes</em><em> </em><em>which</em><em> </em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>reversed</em><em> </em><em>easily</em><em> </em><em>to</em><em> </em><em>form</em><em> </em><em>the</em><em> </em><em>original</em><em> </em><em>substance</em><em>.</em>
<u>Example</u><u>:</u><u>-</u> <em>Melting</em><em> </em><em>of</em><em> </em><em>ice</em><em> </em><em>,</em><em> </em><em>Making</em><em> </em><em>a</em><em> </em><em>solution</em><em>, </em><em> </em><em>Glowing</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>electric</em><em> </em><em>bulb</em><em> </em><em>,</em><em> </em><em>freezing</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>etc</em><em>.</em>
<u>CHEMICAL</u><u> </u><u>CHANGE</u>
<em>Those</em><em> </em><em>changes</em><em> </em><em>in</em><em> </em><em>which</em><em> </em><em>new</em><em> </em><em>substances</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>are</em><em> </em><em>called</em><em> </em><em>chemical</em><em> </em><em>changes</em><em>. </em><em>it</em><em> </em><em>means</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>permanent</em><em> </em><em>changes</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>usually</em><em> </em><em>irreversible</em><em>. </em>
Example:- <em>Burning</em><em> </em><em>of</em><em> </em><em>charcoal</em><em>,</em><em> </em><em>fuels</em><em> </em><em>and</em><em> </em><em>cutting</em><em> </em><em>of</em><em> </em><em>trees</em><em>, </em><em> </em><em>even</em><em> </em><em>digestion</em><em> </em><em>of</em><em> </em><em>food</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>chemical</em><em> </em><em>change</em><em>. </em>
HOPE ITS HELPFULLL
BE BRAINLY.
1.95 or 2 is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.
The correct answer is option b
Explanation:
Data given:
mass of KN
= 45.3 grams
volume = 0.225 litre
molarity =?
atomic mass of KNO3 = 101 grams/mole
molarity is calculated by using the formula:
molarity = 
first the number of moles present in the given mass is calculated as:
number of moles = 
number of moles = 
0.44 moles of KNO3
Putting the values in the equation of molarity:
molarity = 
molarity = 1.95
It can be taken as 2.
The molarity of the potassium nitrate solution is 2.
Since the total amount of valence electrons is 3, it is in group 13 in the periodic table..therefore, it is specified as Boron.✅
Following reaction occurs in the given electrochemical system:

→ Fe +

Thus, under standard conditions
E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
where,

= standard reduction potential of Fe2+/Fe = -0.44 v

= standard reduction potential of Zn2+/Zn = -0.763 v
E(0) = 0.323 v
now, we know that, ΔG(0) =-nFE(0) ............... (1)
Also, Δ

On equating and rearranging equation 1 and 2, we get
K = exp(

)= exp (

) = 8.46 x