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sweet [91]
3 years ago
10

Nina thought of a number. She called her number y. She added 14 to her number, divided the result by 6, and she got 12. What was

y equal to?
Mathematics
1 answer:
Shalnov [3]3 years ago
3 0
Y=58

y/6=12
y=72
72-14=58

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Please answer this question now in two minutes
Igoryamba

Answer: x=6, y=20

Step-by-step explanation:

Since ΔBCD and ΔTUS are congruent triangles, we can set the sides equal to each other.

y=2y-20                           [subtract both sides by 2y]

-y=-20                              [divide both sides by -1]

y=20

--------------------------------------------------------------------------------------

3x+32=9x-4                    [add both sides by 4, and subtract both sides by 3x]

36=6x                              [divide both sides by 6]

x=6

7 0
3 years ago
How many solutions does the following equation have
vampirchik [111]
B= Exactly one solution
-6y+9y= 3y
3y+13=8y-3
3y=8y-16
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7 0
3 years ago
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By selling a watch for Rs. 150, there would be a loss and there would be a proft if it is sold for Rs. 200. If the loss and the
Nuetrik [128]

Rs. 25 loss

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AND Rs. 150 cost.

6 0
2 years ago
Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

  • 8 ≠ 16
<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

  • 169 = 169
<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

  • 34 ≠ 36
<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

\sf \: 25 + 16 = 49

  • 41 ≠ 49
<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

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