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3 years ago

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An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its

internal energy increased by 7265 J. What is the specific heat of the gas?

1 answer:

VMariaS [17]3 years ago

3 0

Not sure if this is right though haha

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what noble gas has the same electron configuration as each of the ions in the following compounds? a. Cesium sulfide b. strontiu

saveliy_v [14]

Answer:

A. Cesium sulfide

Explanation:

looked it up lol

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3 years ago

A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re

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Answer: (3) C

Explanation:

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3 years ago

Draw the reactants using the drawing tool. Keep in mind that one molecule of nitrogen has two bonded atoms, and one molecule of

ANTONII [103]

The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:

$N_2 + 3H_2 \rightarrow 2NH_3$

<h3>What is the equation of the formation of ammonia?</h3>

Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.

Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.

The equation of the reaction is given below as:

$N_2 + 3H_2 \rightarrow 2NH_3$

Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.

Learn more about ammonia gas at: brainly.com/question/7982628

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2 years ago

The way it can be determined which type of atom we have is to figure out____are contained within the nucleus of the atom A.elect

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3 years ago

Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2

erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0

3 years ago