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N76 [4]
3 years ago
15

What do all four of these types of molecules have in common?

Chemistry
1 answer:
nalin [4]3 years ago
3 0
D. They all contain carbon as an important part of their structure.
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After an hour in the cooler the sodas get colder and the ice gets warmer. Which of the following explains these changes correctl
kompoz [17]
Because it’s called heat changes it and melts the ice
6 0
3 years ago
Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of
Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n .  R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

5 0
2 years ago
Read 2 more answers
Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell  = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s)     E∘= −0.45 V

Ag+aq)+e−→Ag(s)         E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻  reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles  and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K  

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592  = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0
3 years ago
When a mixture of 12.0 g of acetylene (c2h2 and 12.0 g of oxygen (o2 is ignited, the resultant combustion reaction produces co2
valina [46]
The product of the complete combustion of any fuel (in this case, acetylene) are indeed water and carbon dioxide. 
Balancing the combustion reaction,
                           C2H2 +(5/2) O2 --> 2CO2 + H2O
The number of moles of C2H2 will be,
                        (12 g) x (1 mole/26 g) = 6/13 mole
Then, the number of moles of O2 is,
                         (12 g) x (1 mole/32 g) = 3/8 mole
Therefore the limiting reaction is the O2. Getting the amount of CO2 and H2O produced from balancing,
             CO2 = (3/8 moles) x (2 moles CO2/ 5/2 mole O2)(44 g/ 1 mole) = 52.8 g
             H2O = (3/8 moles) x (1 mole / 5/2 mole O2)(18 g / 1 mole) = 2.7 g
3 0
3 years ago
Read 2 more answers
What conversion factor is present in almost all stoichiometry calculations?
luda_lava [24]
<h3><u>Answer;</u></h3>

Molar mass

<h3><u>Explanation</u>;</h3>
  • Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
  • A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
  • Molar ratios, or conversion factors, identify the number of moles of each reactant needed to form a certain number of moles of each product.
8 0
3 years ago
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