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romanna [79]
2 years ago
13

1. Which of the following statements pertaining to the ionic solids represented below are true?

Chemistry
1 answer:
alexira [117]2 years ago
3 0

Answer:

B

Explanation:

so A is nosense C and D the question is saying the stament for a being repersentation of solid not whether eletric or not

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(If this is correct, can I have Brainlist?)

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6 0
3 years ago
A lab is done using different metals and the density of the metals are recorded in a data table. What is the independent variabl
vovikov84 [41]

Answer:   The independent variable is the type of metal being used.

{Note:  The "dependent variable" is the "measured density" that corresponds to each of the metals."}.

___________________________________________

Explanation:

___________________________________________

The "independent variable", which is plotted on the "x-axis" (horizontal axis), is the variable that can be "controlled/manipulated".  In this case, this would be the type of metal chosen.

The "dependent variable" , which is plotted on the "y-axis" (vertical axis) is the "obtained value/measurement/result" (that "cannot be controlled/manipulated").

In this case, the "density", which is the "measured value" that corresponds to the selected "meal", is the "dependent variable".

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6 0
3 years ago
How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution
dalvyx [7]
<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})
  2. Multiply:                              \displaystyle 0.024114 \ kg \ CaO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

4 0
2 years ago
Read 2 more answers
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