Question

The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons. Name the element.

Answer 1

Answer:

The four quantum number for each electron will be:

$1s^{2}$

$n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

$2s^{2}$

$n=2;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

$2p^{6}$

$n=1;l=1;\\m=+1,0.-1 \\s=+\frac{1}{2}/-\frac{1}{2}$

$3s^{2}$

$n=3;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

Atomic number = 12

Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

thus m = 0 or +1 or -1

The two electrons in each orbital will have either plus half or minus half spin quantum number