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Orlov [11]
3 years ago
5

Two equal mass balls (one red and the other blue) are dropped from the same height, and rebound off the floor. The red ball rebo

unds to a higher position. Which ball is subjected to the greater magnitude of impulse during its collision with the floor?
Physics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

Red ball

Explanation:

Two ball of equal mass when fall on the surface from the same height means that both balls have same potential energy.

when the ball collides with the floor both ball posses same velocity.

but according to the statement given that red ball rebounds higher position means that the change of the velocity of the red ball is more the blue ball.

so, the change in momentum of the red ball is more than the blue ball which means the impulse during collision of the red ball will be more.

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ECONOMICS !!!!
gulaghasi [49]

Answer:

B

Explanation:

Absolute advantage is the capability of a commercial entity to produce goods using fewer resources compared to rivals. Using the same inputs, an entity with an absolute advantage produces a larger output compared to competitors. It means the firm has a lower marginal cost of production. Therefore, its products will have the lowest prices in the market.  

6 0
2 years ago
How does the mass affect the speed as it rolls down a slope?
VikaD [51]
As we use the Kinetic energy and the equation is 1/2mv^2, changing its mass will change its speed and its energy. So more mass, more speed more energy. also the gravitational potential energy; mass x gravity x height; more mass and more height more speed as it go down to the slope! Hope it helps!
6 0
3 years ago
When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the c
e-lub [12.9K]

Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

dV/dt ∝ V

dV/dt = kV

separating the variables, we have

dV/V = kdt

integrating both sides, we have

∫dV/V = ∫kdt

㏑(V/V₀) = kt

V/V₀ = e^{kt}

Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

k = -0.01

So, V/V₀ = e^{-0.01t}

V = V₀e^{-0.01t}

Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

V = V₀e^{-0.01t}

0.1V₀ = V₀e^{-0.01t}

0.1V₀/V₀ = e^{-0.01t}

0.1 = e^{-0.01t}

to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

㏑(0.01) = -0.01t

So, t = ㏑(0.01)/-0.01

t = -4.6052/-0.01

t = 460.52 s

3 0
3 years ago
A car having an initial velocity of 12 meters per second speed up uniformly to 22 meters per second. This change is made in 4 se
Sonbull [250]

(22-12)/4

10/4

2.5 meters per second sqaured

7 0
3 years ago
Electricity costs 6 cents per kilowatt hour. In one month one home uses one megawatt hour of electricity. How much will the elec
Luda [366]

Answer:

Cost of 1000  kilowatt hour = 6000 cents

Explanation:

Given that

Electricity cost is 6 cents per kilowatt hour.

And we have to found out the cost for one megawatt hour

We know that

1 kilowatt = 1000 watt

1 megawatt = = 1000000 watt

1 megawatt = 1000 kilowatt

1 megawatt hour = 1000 kilowatt hour  

Given that cost of 1 kilowatt hour = 6 cents

So the cost of 1000  kilowatt hour = 6 x 1000 cents

Cost of 1000  kilowatt hour = 6000 cents

3 0
3 years ago
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