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Orlov [11]
3 years ago
5

Two equal mass balls (one red and the other blue) are dropped from the same height, and rebound off the floor. The red ball rebo

unds to a higher position. Which ball is subjected to the greater magnitude of impulse during its collision with the floor?
Physics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

Red ball

Explanation:

Two ball of equal mass when fall on the surface from the same height means that both balls have same potential energy.

when the ball collides with the floor both ball posses same velocity.

but according to the statement given that red ball rebounds higher position means that the change of the velocity of the red ball is more the blue ball.

so, the change in momentum of the red ball is more than the blue ball which means the impulse during collision of the red ball will be more.

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Vinil7 [7]

Answer:A satellite maintains its orbit by balancing two factors its velocity the speed it takes to travel in a straight line and the gravitational pull that Earth has on it. A satellite orbiting closer to the Earth requires more velocity to resist the stronger gravitational pull.

Explanation:

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3 years ago
12. A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of
Margaret [11]
1/2 m/s2
30 Na




I hope this helps!
4 0
3 years ago
The normal force acting on an object and the force of static friction do zero work on the object. However the reason that the wo
spin [16.1K]

Answer:

<em>The normal force is perpendicular to the displacement</em>

<em>The static friction force produces no displacement</em>

Explanation:

Work Done By Special Forces

The work is a physical magnitude that measures the dot product of the force applied to an object by the displacement it produces in it.

W=\vec F\ \vec r

It can be written in its scalar version as

W=F.d.cos\theta

Being F and d the magnitudes of the force and displacement, and \theta the angle between them

If the angle is zero, the work is at maximum, it the angle is 90°, the work is zero. If the angle is between 90° and 180°, the work is negative.

The normal force acts in the vertical direction when the object is being pushed horizontally. It means the angle between the force and the displacement is 90°, thus the work is

W=N.d.cos90^o=0

The work is zero because the force and the displacement are perpendicular

The static friction force exists only when the object is being applied a force of a magnitude not large enough to produce movement, i.e. the object is at rest. If the object is moved, the friction force is still present, but it's called dynamic friction force, usually smaller than the static.

Since in this case, there is no displacement, d=0, and the work is

W=F_r(0)cos180^o=0

3 0
4 years ago
The girl makes a microscope with a 3.0 cm focal length objective and a 5.0 cm eyepiece. The microscope tube length is 10 cm. Use
saul85 [17]

To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".

The overall magnification of microscope is

M = \frac{Nl}{f_ef_0}

Where

N = Near point

l = distance between the object lens and eye lens

f_0= Focal length

f_e= Focal of eyepiece

Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm

Replacing,

M = \frac{25*10}{3*5}

M = 16.67\approx 17\\

Therefore the correct answer is C.

3 0
3 years ago
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