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Orlov [11]
3 years ago
5

Two equal mass balls (one red and the other blue) are dropped from the same height, and rebound off the floor. The red ball rebo

unds to a higher position. Which ball is subjected to the greater magnitude of impulse during its collision with the floor?
Physics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

Red ball

Explanation:

Two ball of equal mass when fall on the surface from the same height means that both balls have same potential energy.

when the ball collides with the floor both ball posses same velocity.

but according to the statement given that red ball rebounds higher position means that the change of the velocity of the red ball is more the blue ball.

so, the change in momentum of the red ball is more than the blue ball which means the impulse during collision of the red ball will be more.

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A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the
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Answer:

The bin moves 0.87 m before it stops.

Explanation:

If we analyze the situation and apply the law of conservation of energy to this case, we get:

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Hence, the equation becomes:

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d = (0.5)(Vi² - Vf²)/μg

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d = distance moved by bin before coming to stop = ?

Therefore,

d = (0.5)[(1.6 m/s)² - (0 m/s)²]/(0.15)(9.8 m/s²)

<u>d = 0.87 m</u>

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