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Natali5045456 [20]
3 years ago
11

The length of a football field is closest to (1) 1000 cm (3) 1000 km (2) 1000 dm (4) 1000 mm

Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0
The length of a football field is closest to 1000dm, since dm stands for decimeter, which is about one tenth of a meter. Although it should be noted that this is not exact. 
Sergeu [11.5K]3 years ago
5 0

For this case, the first thing you should know is that the length of a football field is around 100 meters.

We must then look for a measure close to this value.

We have the following unit conversion:

1 meter = 10 decimeters

Applying the conversion we have:

(1000 dm)*(\frac{1}{10} \frac{m}{dm}) = 100 m

Therefore, the measure closest to a soccer field is:

1000 dm

Answer:

The length of a football field is closest to:

(2) 1000 dm

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Answer:

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Explanation:

As the skydiver falls to the Earth, she experiences friction in the form of air resistance which tries to slow her down and is proportional to the her velocity. So it cannot have a positive acceleration as it acts in opposite direction to slow her down.

Inertia during skydiving is experienced when we open an parachute, the parachute slows down the speed of are descent hence changing our inertia of motion with a velocity.

Only the Earth's, gravitational field has an positive acceleration as it pulls us towards the Earth, hence increasing our velocity.

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Why can objects be made to float in a magnetic field?
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A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?
vovikov84 [41]

Answer:

30N in the direction the 45N acts.

Explanation:

Fnet = F1 + F2 (the vector sum of the forces)

Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:

Fnet = 45 - 15

Fnet = 30N

Since the answer is positive, it is in the direction the 45N force acts.

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2 years ago
Which of the following is NOT an exercise myth?
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2 years ago
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
kykrilka [37]

Explanation:

It is given that,

Mas of the car, m_1=1170\ kg

Initial speed of the car, u_1=25\ m/s

Mass of the truck, m_2=9800\ kg

Initial speed of the car, u_2=20\ m/s

Final speed of the car, v_1=18\ m/s

(a) It is a case of elastic collision. Let v_2 is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{1170\times 25+9800\times 20-1170\times 18}{9800}

v_2=20.83\ m/s

(b) Initial kinetic energy is given by :

k_i=\dfrac{1}{2}(m_1u_1^2+m_2u_2^2)

k_i=\dfrac{1}{2}\times (1170\times (25)^2+9800\times (20)^2)

k_i=2325625\ J

Final kinetic energy is given by :

k_f=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

k_f=\dfrac{1}{2}\times (1170\times (18)^2+9800\times (20.83)^2)

k_f=2315595.61\ J

The change in mechanical energy of the car truck system in the collision:

\Delta K=k_f-k_i

\Delta K=2315595.61-2325625

\Delta k=-10029.39\ J

The loss in kinetic energy is 10029.39 Joules.

(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.

Hence, this is the required solution.

6 0
2 years ago
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