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Shalnov [3]
2 years ago
11

PLEASE HELP!! ILL MARK BRAINLYEST!!

Physics
1 answer:
zheka24 [161]2 years ago
5 0
The Answer is true hope this helps
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3 years ago
I am looking for this answer :Which shows a correct order of steps in the scientific method?
ELEN [110]

Answer:

Explanation:

make observations, draw conclusions, develop a hypothesis, analyze data.

6 0
2 years ago
Which term means the weight of air measured in units of force per area?
Norma-Jean [14]
Force per area is pressure so I think the answer would be air pressure. Relative pressure sounds like it is a measure of pressure relative to something else.
3 0
3 years ago
IP A spark plug in a car has electrodes separated by a gap of 6.5×10−2 in . To create a spark and ignite the air-fuel mixture in
emmainna [20.7K]

Answer:

a.) V=5283.2 \ V

b.) V=4064\ V

Explanation:

<u>Electric Field and Potential Difference</u>

There are several conditions that must be met for a spark to be created into an air gap. Once the physical conditions are fixed, a minimum electric field is necessary for the spark to be initiated. Let s be the separation between the electrodes and V their potential difference. The electric field is

a.)

\displaystyle E=\frac{V}{s}

Solving for V

V=E.s

The separation is

s= 5.5\cdot 10^{-2}\ in=0.001651 \ m

Thus the potential difference is

V=3.2\cdot 10^{6}\ V/m\times 0.001651 \ m

V=5283.2 \ V

b.) If the separation was greater, the applied voltage needs to be greater if the electric field has to be constant. One possible measure to keep electrodes as close as possible is to build them as sharp edges. It gives the spark an easier path to travel to.

If the separation is 0.05 inches =0.00127 m

V=3.2\cdot 10^{6}\ V/m\times 0.00127 \ m

V=4064\ V

7 0
3 years ago
At temperatures near absolute zero, Bc approaches 0.142 T for vanadium, a type-I superconductor. The normal phase of vanadium ha
ioda

Answer:

b) field is zero,  c) the magnetic field does not change in intensity or direction

e) M = -H = Bo /μ₀ ,  g)  M = 0

Explanation:

Part b

superconductors are formed by so-called Coper pairs that are electrons linked through a distortion in the network, this creates that they must be treated as an entity so we have an even number of charge carriers and the material must behave with diamagnetic , Meissner effect, consequently the magnetic field inside its superconductor is zero

the correct answer is Zero

Part c

 outside the superconducting cylinder the magnetic field does not change in intensity or direction

Part E

Magnetization is defined by the equation

       B = μ₀ (H + M)

with field B it is zero inside the superconductors

        M = -H = Bo /μ₀

         

where Bo is the magnetic induction in the normal state

Part g

 As outside the cylinder there is no material zero magnetization

        M = 0

6 0
2 years ago
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