Complete Question 
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?
Answer:
The value  is   
  
Explanation:
From the question we are told that 
    The semi - major axis of the rocky debris  
    The semi - major axis of  Planet D is  
     The orbital  period of planet D is  
Generally from Kepler third law 
           
Here T is the  orbital period  while a is the semi major axis 
So  
         
=>     ![T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }](https://tex.z-dn.net/?f=T_R%20%20%3D%20T_D%20%2A%20%20%5B%5Cfrac%7Ba_R%7D%7Ba_D%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D) 
  
=>     ![T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }](https://tex.z-dn.net/?f=T_R%20%20%3D%2018.164%20%20%2A%20%20%5B%5Cfrac%7B%2045%7D%7B60%7D%20%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D)
=>       
  
    
 
        
             
        
        
        
<h3>
Answer:</h3>
 117.6 Joules 
<h3>
Explanation:</h3>
<u>We are given;</u>
- Force of the dog is 24 N 
- Distance upward is 4.9 m 
We are required to calculate the work done
- Work done is the product of force and distance 
- That is; Work done = Force × distance
- It is measured in Joules.
In this case;
Force applied is equivalent to the weight of the dog.
Work done = 24 N × 4.9 m 
                   = 117.6 Joules 
Hence, the work done in lifting the dog is 117.6 Joules
 
        
        
        
I think it 32, but i’m not sure
        
                    
             
        
        
        
Answer:
General intelligence refers to the existence of a broad mental capacity that influences performance on cognitive ability measures. 
Specific intelligence refers to a person's aptitude in individual 'modalities' or abilities rather than the more general understanding of intelligence.
Explanation:
 
        
                    
             
        
        
        
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:

where 

 is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:

where

 is the final speed of the sled

 is the initial speed

 is the distance covered
By rearranging the equation, we find d:
