Question

A velocity selector consists of a uniform electric field of 3.4*10^6 V/m and a uniform magnetic field of 42.0 mT, perpendicular to each other, through which a beam of muons is fired (muons are a particle with 207 times the mass and the same charge as an electron). If the muons travel in a straight line, then what must be their velocity

Answer 1

Answer:

The velocity of muons is $8.1\times 10^{7}m/s$.

Explanation:

Electric field, E = $3.4\times 10^{6} V/m$

Magnetic field, B = 42 mT = 0.042 T

mass, m =207 x mass of electron

charge, q = $1.6\times 10^{-19}C$

Let the velocity is v.

The magnetic force on the charge is balanced by the electric force.

q v B sin 90 = q E

v x B = E

v x 0.042 = $3.4\times 10^6$

v = $8.1\times 10^{7}m/s$