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Vaselesa [24]
2 years ago
15

A velocity selector consists of a uniform electric field of 3.4*10^6 V/m and a uniform magnetic field of 42.0 mT, perpendicular

to each other, through which a beam of muons is fired (muons are a particle with 207 times the mass and the same charge as an electron). If the muons travel in a straight line, then what must be their velocity
Physics
1 answer:
Blizzard [7]2 years ago
8 0

Answer:

The velocity of muons is 8.1\times 10^{7}m/s.

Explanation:

Electric field, E = 3.4\times 10^{6} V/m

Magnetic field, B = 42 mT = 0.042 T

mass, m =207 x mass of electron

charge, q = 1.6\times 10^{-19}C

Let the velocity is v.

The magnetic force on the charge is balanced by the electric force.

q v B sin 90 = q E

v x B = E

v x 0.042 = 3.4\times 10^6

v = 8.1\times 10^{7}m/s

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