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3 years ago

What shape best describes the cross section cut at an angle to the base of a right rectangular prism?

Mathematics

2 answers:

irga5000 [103]3 years ago

7 0

A trapezoid should be the answer.

Hope this helps you.

ValentinkaMS [17]3 years ago

5 0

T r i a n g l e because if you cut it it becomes a triangle

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Per

Levart [38]

Answer:

1. 5200+5200=10400

2. 10400-361=10039

Branlyist pls

8 0

3 years ago

at memorial hospital 9 of the 12 babies born on Tuesday were boys In simplest form What fraction of the babies born on Tuesday w

Papessa [141]

9/12 = (9/3) / (12/3)= 3/4.

3/4 of the babies born on Tuesday were boys~

5 0

3 years ago

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3+2⋅[(2+1)⋅5+8] need the answer please

s2008m [1.1K]

Hey!

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Solution:

Remember to follow PEMDAS!

= 3 + 2 ⋅ [(2 + 1) ⋅ 5 + 8]

= 3 + 2 ⋅ [(3) ⋅ 5 + 8]

= 3 + 2 ⋅ [(15) + 8]

= 3 + 2 ⋅ [23]

= 3 + 46

= 49

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Answer:

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Hope This Helped! Good Luck!

8 0

3 years ago

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A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

Y = 2x^2+4x-3 If you were to do a quadratic formula then what is a,b, and c?

jasenka [17]

Part 1:
a = 2
b = 4
c = -3
Part 2: the parabola will open up
Part 3: axis of symmetry x = -1

6 0

3 years ago

Read 2 more answers