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aksik [14]
3 years ago
10

the student plotted distance v.s time graph in which the line sloped downward. Is the graph correct?

Physics
1 answer:
Leni [432]3 years ago
7 0

It could be, depending on WHAT distance was graphed,
and how the student labeled the graph's axes.


Most likely, however, she probably drew the graph ...

-- with time on the x-axis increasing to the right,

-- with distance on the y-axis increasing upward,

-- to show the distance FROM the starting point
   NOT the distance remaining to the destination. 

If that's how she set it up, or if any two of these items are
the other way around, then the line could not slope downward. 
THAT would say that the distance from the starting point is
decreasing as time goes on, or the distance remaining to the
destination is increasing as time goes on.  That would be silly.

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Answer : The heat rejected by the system is 1000 J

Explanation :

As per first law of thermodynamic,

q=\Delta U+w

where,

\Delta U = internal energy  of the system

q = heat  added or rejected by the system

w = work done of the system

First we have to determine the internal energy for 30 grams of gas.

As, 1 gram of gas has internal energy = 200 J

So, 30 grams of gas has internal energy = 200 × 30 = 6000 J

Now we have to determine the heat of the system.

q=\Delta U+w

\Delta  = -6000 J

w = 5000 N.m = 5000 J

Now put all the given values in the above formula, we get:

q=-6000J+5000J

q=-1000J

The negative sign indicate that the heat rejected by the system.

Hence, the heat rejected by the system is 1000 J

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3 years ago
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