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loris [4]
3 years ago
9

In the food web shown above, which of the following organisms can be classified as a tertiary consumer?

Physics
2 answers:
Anvisha [2.4K]3 years ago
5 0
Hello,

Here is your answer:

The proper answer to this question is option A "puffin".

Your answer is A.

If you need anymore help feel free to ask me!

Hope this helps!
natima [27]3 years ago
3 0
A? If I’m wrong sorry. Have a good day
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A bubble of air is rising up through the ocean. When it is at a depth of 20.0 m below the surface, where the temperature is 5.00
kotegsom [21]

Answer:

the volume is 0.253 cm³

Explanation:

The pressure underwater is related with the pressure in the surface through Pascal's law:

P(h)= Po + ρgh

where Po= pressure at a depth h under the surface (we assume = 1atm=101325 Pa) , ρ= density of water ,g= gravity , h= depth at h meters)

replacing values

P(h)= Po + ρgh = 101325 Pa + 1025 Kg/m³ * 9.8 m/s² * 20 m = 302225 Pa

Also assuming that the bubble behaves as an ideal gas

PV=nRT

where

P= absolute pressure, V= gas volume ,n= number of moles of gas, R= ideal gas constant , T= absolute temperature

therefore assuming that the mass of the bubble is the same ( it does not absorb other bubbles, divides into smaller ones or allow significant diffusion over its surface) we have

at the surface) PoVo=nRTo

at the depth h) PV=nRT

dividing both equations

(P/Po)(V/Vo)=(T/To)

or

V=Vo*(Po/P)(T/To) = 0.80 cm³ * (101325 Pa/302225 Pa)*(277K/293K) = 0.253 cm³

V = 0.253 cm³

3 0
3 years ago
Which kind of energy transformation occurs during skydiving? A) mechanical to gravitational B) gravitational to kinetic C) kinet
Aleks [24]

B) gravitational to kinetic

Explanation:

The skydiver, when he is located at a certain height h above the ground, possesses gravitational potential energy, equal to:

U=mgh

where m is the mass of the skydiver, g is the gravitational acceleration and h is the height above the ground. As he falls, its height h decreases, while his speed v increases, so part of the gravitational potential energy is converted into kinetic energy, which is given by

K=\frac{1}{2}mv^2

so, we see that as v increases, the kinetic energy increases. Therefore the correct answer is

B) gravitational to kinetic

7 0
3 years ago
Read 2 more answers
The density of 2 kilograms of iron on Earth's surface is
Eduardwww [97]

Answer:

B. The same on the moon.

Explanation:

The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.

Density = \frac{Mass}{Volume}

When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.

Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.

So, the correct option is:

<u>B. The same on the moon.</u>

5 0
3 years ago
Note: Use g=9.8 N/kg in this assignment.
Karolina [17]

Answer:

16.12

thistle seed oil benefits to be deposited on your way

5 0
2 years ago
A 15 kg runaway grocery cart runs into a spring with spring constant 230 N/m and compresses it by 56 cm .What was the speed of t
liubo4ka [24]

To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

KE = \frac{1}{2} mv^2

And the potential energy is

PE = \frac{1}{2} kx^2

Here,

m = mass

v = Velocity

x = Displacement

k = Spring constant

There is equilibrium, then,

KE = PE

\frac{1}{2} mv^2 = \frac{1}{2} kx^2

Our values are given as,

x=0.56m\\k=230N/m\\m=15kg

Replacing we have that

\frac{1}{2} (15)v^2 = \frac{1}{2} (230)(0.56)^2

v = 2.19m/s

Therefore the speed of the cart is 2.19m/s

3 0
3 years ago
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