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vovikov84 [41]
3 years ago
5

If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f

ield in the region R>R3, where the radial distance R is measured from the metal cylinder's axis. Assume d<(R2−R1). Express your answer in terms of the variables ρE, R1, R2, R3, d, R, and appropriate constants.
Physics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

E =  ρ ( R1²) / 2 ∈o R

Explanation:

Given data

two cylinders are parallel

distance = d

radial distance = R

d < (R2−R1)

to find out

Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants

solution

we have two parallel cylinders

so area is 2 \pi R × l

and we apply here gauss law that is

EA = Q(enclosed) / ∈o   ......1

so first we find  Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( \pi R1² × l )

so put all value in equation 1

we get

EA = Q(enclosed) / ∈o

E(2 \pi R × l)  = ρ ( \pi R1² × l ) / ∈o

so

E =  ρ ( R1²) / 2 ∈o R

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Nadusha1986 [10]

Answer:

True

Explanation:

This the exact example I went over with my class during school and he said it word from word

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3 years ago
Suppose you want to test the hypothesis that plants grow taller when they receive more sunlight. Identify and independent variab
ollegr [7]
The result that should be established is in the form
y = f(x) 
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y =  height (growth) that corresponds to the amount of sunlight. Therefore y depends on x.

Clearly,
x, the amount of sunlight is the independent variable. It can be controlled.
y, the measured amount of growth is the dependent variable.

Answer:
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4 years ago
The current supplied by a battery slowly decreases as the battery runs down. Suppose that the current as a function of time is:
ludmilkaskok [199]

Answer: 8.1 x 10^24

Explanation:

I(t) = (0.6 A) e^(-t/6 hr)

I'll leave out units for neatness: I(t) = 0.6e^(-t/6)

If t is in seconds then since 1hr = 3600s: I(t) = 0.6e^(-t/(6 x 3600) ).

For neatness let k = 1/(6x3600) = 4.63x10^-5, then:

I(t) = 0.6e^(-kt)

Providing t is in seconds, total charge Q in coulombs is

Q= ∫ I(t).dt evaluated from t=0 to t=∞.

Q = ∫(0.6e^(-kt)

= (0.6/-k)e^(-kt) evaluated from t=0 to t=∞.

= -(0.6/k)[e^-∞ - e^-0]

= -0.6/k[0 - 1]

= 0.6/k

= 0.6/(4.63x10^-5)

= 12958 C

Since the magnitude of the charge on an electron = 1.6x10⁻¹⁹ C, the number of electrons is 12958/(1.6x10^-19) = 8.1x10^24 to two significant figures.

5 0
4 years ago
Uranus is now completing its ____ orbit around the sun since its discovery.
Ket [755]

Answer:

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6 0
2 years ago
1) A crane uses an average force of 5,200 N to lift a girder 25 m. How much work does the crane do on the girder?
Andrej [43]

Answer:

1) 130, 000 J

2) 1 J

Explanation:

1)

Work done is product of force in Newtons and distance in meters

W=Fd

Given an average force of 5,200 N and distance of 25 m then we evaluate that

Work done=5200*25=130, 000 Nm or Joules

2)

Similarly, for the second question, given force of 1N and distace of 1 m then the work done will be

W=1*1=1 J

8 0
3 years ago
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