Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s
The equation for power is P=w/t, where w=work done in joules and t=time in seconds.
in this case:
p=w/t
p=3500/25
p=140
so, the boat was using 140 watts of power.
Time = (distance covered) / (speed)
Time = (224 mi) / (56 mi/hr)
<em>Time = 4 hours</em>
Answer:
W = 2.74 J
Explanation:
The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.
This is the electrostatic equivalent of the work-energy theorem.
where the potential energy is defined as follows
Let's first calculate the distance 'r' for both positions.
Now, we can calculate the potential energies for both positions.
Finally, the total work done on the moving particle can be calculated.
Answer:
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Explanation:
D. dopamine
