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WARRIOR [948]
3 years ago
10

Linolenic acid (C18H30O2 - M.W. = 278.42 g/mol) reacts with hydrogen gas according to the equation: C18H30O2 + 3H2 (g) → C18H36O

2 What volume of hydrogen gas, as measured at P = 1.00 atm and T = 273.15 K, is required to react with 10.5 g of linolenic acid in this reaction?
Chemistry
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

2.53 L is the volume of H₂ needed

Explanation:

The reaction is: C₁₈H₃₀O₂ + 3H₂ → C₁₈H₃₆O₂

By the way we can say, that 1 mol of linolenic acid reacts with 3 moles of oxygen in order to produce, 1 mol of stearic acid.

By stoichiometry, ratio is 1:3

Let's convert the mass of the linolenic acid to moles:

10.5 g . 1 mol / 278.42 g  = 0.0377 moles

We apply a rule of three:

1 mol of linolenic acid needs 3 moles of H₂ to react

Then, 0.0377 moles will react with (0.0377 . 3 )/1 = 0.113 moles of hydrogen

We apply the Ideal Gases Law to find out the volume (condition of measure are STP) → P . V = n . R . T → V = ( n . R .T ) / P

V = (0.113 mol . 0.082 L.atm/mol.K . 273.15K) 1 atm = 2.53 L

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4 years ago
How many moles of CaO will be produced from 23.9 g of Ca?<br>2Ca(s) + O2(g) – 20:0(3)<br>mol​
inessss [21]

Answer:

0.6 moles of CaO will produced.

Explanation:

Given data:

Mass of calcium = 23.9 g

Moles of CaO produced = ?

Solution:

Chemical equation:

2Ca + O₂ → 2CaO

Number of moles of calcium:

Number of moles = mass/ molar mass

Number of moles = 23.9 g / 40 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of calcium and CaO.

            Ca         :          CaO

              2          :          2

            0.6         :        0.6

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4 0
3 years ago
Determine the molarity of 50 mL of HCl solution with unknown concentration, titrated with 75 mL of 4.0 M NaOH.
Aleks04 [339]

Answer:

The answer to your question is 6.0M, I know that you said it was not the answer, but it is. Check the significant figures.

Explanation:

Data

Molarity = ?

volume of HCl = 50 ml

volume of NaOH = 4 M

volume = 75 ml

Balanced chemical reaction

        HCl  +  NaOH  ⇒  NaCl  +  H₂O

Process

1.- Calculate the moles of NaOH

Molarity = moles/volume

moles = Molarity x volume

moles = 4 x 0.075

moles = 0.3 of NaOH

2.- Use proportions to calculate the moles of HCl

                 1 mol of NaOH ----------------- 1 mol of HCl

                0.3 moles of NaOH ----------  x

                 x = (0.3 x 1)/1

                 x = 0.3 moles of HCl

3.- Calculate the molarity of HCl

Molarity = 0.3/0.05

Molarity = 6.0 M

8 0
4 years ago
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