Answer:
The time the two planes will meet is 1.43 hours
Step-by-step explanation:
Given;
speed of the first plane in positive direction, = 40 mph
speed of the second plane in negative direction(opposite direction) = -100 mph
distance between the two planes = 200 miles
Let the time the two planes will meet = t
the position of the first plane at this time "t" = 40t
the position of the second plane at this time "t" = -100t
(40t)>--------------------------------<(-100t), this space between them is 200 miles.
Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.
40t - (-100t) = 200
40t + 100t = 200
140t = 200
t = 200 / 140
t = 1.43 hours
Therefore, the time the two planes will meet is 1.43 hours
Now I'm not completely sure of this answer but by my calculations the member can visit at least 36 times with $42.
STEP-BY-STEP SOLUTION:
Profit = $25
Cost = $125
Profit as a % of the cost price
= ( 25 / 125 ) × 100%
= ( 1 / 5 ) × 100%
= 20%
ANSWER: 20%
