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3 years ago

14

What is the empirical mass of SO2? Answer using four significant figures.

2 answers:

zhuklara [117]3 years ago

5 0

The atomic mass is 64.07

timofeeve [1]3 years ago

3 0

The atomic mass is 64.07

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If an atom contains 60 protons, 60 electrons, and 89 neutrons. What is the mass number of the atom? *

Diano4ka-milaya [45]

To come up with the mass of the atom is you add the protons with the neutrons

so you have
60+89=149

3 0

4 years ago

For the reaction: h2nnh2 (aq) + h2o(l) ⇌ h2nnh3+(aq) + oh- (aq) determine the conjugate base of the acid?

never [62]

In this reaction, water acts as the base and donates a proton to hydrazine (H2NNH2). Hydrazine becomes protonated: [N2H5]<span>+ And thus hydrazine in this reaction is actually a base. The conjugate base of the acting acid H2O is OH- (hydroxide ion).</span>

4 0

4 years ago

Read 2 more answers

A rock has a mass of 127 grams and displaces 32.1 mL of water. what is the density of the rock?

anzhelika [568]

Answer:

3.96 g/cm^3

Explanation:

5 0

4 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

The reaction for producing glucose in plants, called photosynthesis, is 6 CO 2 + 6 H 2 O light −−→ C 6 H 12 O 6 + 6 O 2 6CO2+6H2

Nostrana [21]

Answer:

30.36moles

Explanation:

6CO2 + 6H2O → C6H12O6 + 6O2

From the equation above,

6moles of H2O are required to produce 1 mole of C6H12O6

Therefore, Xmol of H2O will be require to 5.06moles of C6H12O6 i.e

Xmol of H2O = 6 x 5.06 = 30.36moles

Therefore, 30.36moles of H2O are needed.

5 0

3 years ago