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tigry1 [53]
3 years ago
9

Joel was looking at the side of a three-dimensional shape and saw a rectangle. Which three-dimensional shape could he have been

looking at?
Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0
Rectangular prism is the answer
34kurt3 years ago
5 0
A rectangular prism
You might be interested in
The 12th term and the sim of 1+3+5+7+.....
zzz [600]

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term


7 0
4 years ago
Chris opened up a new credit card and credit line with U.S bank. He is paying a 15% APR on all new purchases
Nana76 [90]

Answer:

Which one does not belong to the group

8 0
2 years ago
A survey of 7th graders at Sandy Middle School found that 152 students were enrolled in Art classes and 44 of those students are
sammy [17]

Answer:

354

Step-by-step explanation:

44+310=354. ejeihrbebeh

5 0
3 years ago
Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit
lukranit [14]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let \hat p = <u><em>the sample proportion of defectives</em></u>.

The z-score probability distribution for the sample proportion is given by;

                         Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

            n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P(\hat p > 0.13)

         P(\hat p > 0.13) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  } > \frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}}  } ) = P(Z > -2.74) = P(Z < 2.74)

                                                                      = <u>0.99693</u>

The above probability is calculated by looking at the value of x = 2.74 in the  table which has an area of 0.99693.

7 0
3 years ago
On Gavin's math test, 3/8 of the questions are division problems. Of the division problems, 4/9 of the problems he got incorrect
deff fn [24]
Something is strange in the wording of the question.  "Of the division problems, 4/9 of the problems he got incorrect.  What fraction of the division problems did Gavin get incorrect?" :)  Well 4/9 of course.  One statement answers another.  Maybe they wanted the fraction of those wrong answers were in relation to the entire test???


\frac {3}{8} * \frac {4}{9} = \frac {12}{72} = \frac {1}{6}

...............
6 0
3 years ago
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