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dmitriy555 [2]
2 years ago
8

Is this the correct graphing for the inequality 2c<=100? i’ll mark brainliest please help!!!

Mathematics
1 answer:
zepelin [54]2 years ago
5 0

Answer:

Step-by-step explanation:

2c≤100 |:2

c≤50

So the correct graphing would be (-∞;50]

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What is 36 percent of 210?
ohaa [14]

Hey there!

Let's start by finding what 1% of 210 is.

This can be done by dividing 210 by 100, since 1% is the same as 1/100 of something.

210 ÷ 100 = 2.1

To find 36%, we can multiply 2.1 by 36.

2.1 x 36 = 75.6

So, 36% of 201 is 75.6.

Hope this helps!

4 0
3 years ago
Can someone help me with this maths equations please?
ale4655 [162]

Answer:

T=4B+10C

Step-by-step explanation:

for every bag there are 4 doughnuts

for every carton there are 10 doughnuts

4 0
2 years ago
Pls, help anyone- it's due tomorrow!
harina [27]

Answer: 65.94

Step-by-step explanation:

Find the area of the middle circle.

3.14 x 2² = 12.56

Pretend the white area doesn't exist and find the area of the shaded region.

3.14 x 5² = 78.5

Then subtract.

78.5 - 12.56 = 65.94

6 0
2 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
MATH show you work pleaseee i really need this.
dlinn [17]

Answer:

The answer for 1 is B and the answer for 2 is A

Step-by-step explanation:

Because 8-5=3 and 3/3=1 And for 2 -4x6= -24 + 29 = 5

Hope it helps! ^w^

8 0
3 years ago
Read 2 more answers
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