3 years ago

Helppppppppppppppppppppppppppppppppppppp

Mathematics

1 answer:

ipn [44]3 years ago

5 0

[ a⁵ (a²b³)⁵ ] / [ a²b⁻² ]

[ a⁵ (a¹⁰b¹⁵) ] / [ a²b⁻² ]

[ a⁵⁰ b⁷⁵ ] / [ a²b⁻² ]

I think this: a⁴⁸b⁷⁷ is the answer.

Hope this helps :)

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