Answer:
This could represent something like sliding a small rock across an icy lake.
Explanation:
A 20N force of gravity (weight), and 20N normal force exerted back onto the object imply it is on the ground and has no vertical motion. There is a net force of 0N
An 80N force to the left and a 5N force to the right create a net force of 75N to the left. This means that there is a force acting on the object that makes it accelerate to the left. 80N represents a push or pull force and 5N represents a relatively small frictional force due to the object being slid on a surface such as steel or in this case ice.
Answer:
Explanation:
The centripetal force experienced by the steel toolbox is provided by the friction between the toolbox and the bed of the truck.
Therefore,
--------------------------------(1)
Here,
v - speed of truck
m - mass of toolbox
r - radius of curve around which the truck is turning
f - frictional force
μmg
In order to obtain Vmax, frictional force must also be max
Thus,
f = μmg--------------------------------------------------(2)
Substitute (2) in (1)
μmg
μgr
g - 9.8 m/
The standard value of coefficient of static friction between steel and steel is
μ ≈ 0.7
Therefore,
Answer:
The only work done is when the person lifts the sack over a distance, W = 78.48 [N]
Explanation:
We have to remember the definition of work, which tells us that work is the result of a force by a distance, we must apply this concept in each of the movements of the person in the problem described.
W = F * d
where:
F = force [N]
d = distance [m]
The force is given by the producto of the mass by the gravity.
F = 5 * 9.81 = 49.05 [N]
W = 49.05 * 1.6 = 78.48 [N]
Answer:
the inductive reactance of the coil is 1335.35 Ω
Explanation:
Given;
inductance of the coil, L = 250 mH = 0.25 H
effective current through the coil, I = 5 mA
frequency of the coil, f = 850 Hz
The inductive reactance of the coil is calculated as;
Therefore, the inductive reactance of the coil is 1335.35 Ω