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vaieri [72.5K]
3 years ago
9

You're driving your pickup truck around a curve that has a radius of 17 m.

Physics
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

v = 10.8 m/s^{2}

Explanation:

The centripetal force experienced by the steel toolbox is provided by the friction between the toolbox and the bed of the truck.

Therefore,

\frac{mv^{2} }{r} = f--------------------------------(1)

Here,

v - speed of truck

m - mass of toolbox

r - radius of curve around which the truck is turning

f - frictional force

f \leq μmg

In order to obtain Vmax, frictional force must also be max

Thus,

f = μmg--------------------------------------------------(2)

Substitute (2) in (1)

\frac{mv^{2} }{r} =  μmg

v^{2} =   μgr

g - 9.8 m/s^{2}

The standard value of coefficient of static friction between steel and steel is

μ ≈ 0.7

Therefore,

v = 10.8 m/s^{2}

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A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull
Kaylis [27]

Answer:

 Δt'/ T% = 90.3%

Explanation:

Simple harmonic movement is described by the expression

         x = A cos (wt)

we find the time for the two points of motion

x = - 0.3 A

        -0.3 A = A cos (w t₁)

         w t₁ = cos -1 (-0.3)

         

remember that angles are in radians

        w t₁ = 1.875 rad

x = 0.3 A

        0.3 A = A cos w t₂

        w t₂ = cos -1 (0.3)

         w t₂ = 1,266 rad

         

Now let's calculate the time of a complete period

x= -A

        w t₃ = cos⁻¹ (-1)

        w t₃ = π rad

this angle for the forward movement and the same time for the return movement in the oscillation to the same point, which is the definition of period

         T = 2 t₃

         T = 2π / w     s

now we can calculate the fraction of time in the given time interval

        Δt / T = (t₁ -t₂) / T

        Δt / T = (1,875 - 1,266) / 2pi

        Δt / T = 0.0969

 

This is the fraction for when the mass is from 0 to 0.3, for regions of oscillation of greater amplitude the fraction is

         Δt'/ T = 1 - 0.0969

         Δt '/ T = 0.903

         Δt'/ T% = 90.3%

4 0
3 years ago
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