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Montano1993 [528]
3 years ago
12

You carry a 5 kg sack of potatoes across the store for 5 minutes, and you wait in line holding it for 30 seconds before you get

tired and drop it. You then lift the sack of potatoes upwards for 160 cm and place it on the counter. How much work did you do at the store?
Physics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

The only work done is when the person lifts the sack over a distance, W = 78.48 [N]

Explanation:

We have to remember the definition of work, which tells us that work is the result of a force by a distance, we must apply this concept in each of the movements of the person in the problem described.

W = F * d

where:

F = force [N]

d = distance [m]

The force is given by the producto of the mass by the gravity.

F = 5 * 9.81 = 49.05 [N]

W = 49.05 * 1.6 = 78.48 [N]

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a toboggan loaded with vacationing students (total weight 1300 N) slides down a slope at 30 degrees and there is no friction. wh
sasho [114]

Answer:

The acceleration of the sliding toboggan is, a = 4.9 m/s²

Explanation:

Given data,

The total weight of the toboggan, W = 1300 N

The slope is, Ф = 30°

The acceleration of a body under the influence of the gravitational field does not depend on its mass, size and shape in the absence of the air resistance.

Therefore,

The acceleration of the toboggan is given by the formula,

                           a = g Sin Ф

Substituting the given values in the above equation,

                           a = 9.8 x Sin 30°

                              = 4.9 m/s²

Hence, the acceleration of the sliding toboggan is, a = 4.9 m/s²

4 0
3 years ago
The mass of 2 cm3 of gold is 38.6 grams. find the density of the gold. Could you please help me??
Alex Ar [27]

Density = mass/ volume (so here this is how you would solve the problem)

<span>D = 38.6 g/ 2 cm3 (first step)</span>

<span>D= 19.3 g/cm3  ( Do math and then you would get this)</span>

<span>
</span>

<span>Hope this helps!! :) </span>


6 0
4 years ago
Priya is responsible for collecting canned food along three different streets for her school's annual Thanksgiving Food Drive. S
AveGali [126]
Good luck sorry don’t know the answer
8 0
3 years ago
A sound wave traveling at 343 m/s is emitted by the foghorn of a tugboat. an echo is heard 2.80 s later. how far away is the ref
Nostrana [21]
The echo is heard 2.80 s later, this means this is the time the sound takes to travel to the reflecting object and then back to us. So, during this time, the sound wave has covered the distance L between us and the object twice:
S=2L
The speed of the sound wave is: v=343 m/s, and since it is moving by uniform motion, we can find the distance covered by the wave using
S=vt=(343 m/s)(2.80 s)=960 m
And we said this corresponds to twice the distance between us and the reflecting object, so:
L= \frac{S}{2} = \frac{960 m}{2} =480 m
so, the object is 480 meters away.
3 0
3 years ago
If there is no gravity what will happen to earth?
Serga [27]
Wouldn't everything fall?
7 0
3 years ago
Read 2 more answers
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