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alukav5142 [94]
4 years ago
12

Which statement describes an endothermic reaction? A. Energy is released by the reaction. B. Energy is absorbed by the reaction.

C. No energy is transfered by the reaction. D. Energy is created in the reaction. ​
Physics
1 answer:
tigry1 [53]4 years ago
8 0

Answer:

It's B energy is absorbed by the reaction,hope this helps !:).

Explanation:

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A 4 kg object is moving at a speed of 5 m/sec. How much kinetic energy does the object have? A. 10 joules B. 20 joules C. 50 jou
sp2606 [1]

Answer:

A. 10 joules

Explanation:

Given parameters:

Mass of object  = 4kg

Speed  = 5m/s

Unknown:

Kinetic energy of the the object  = ?

Solution:

Kinetic energy is the energy due to a moving body.

So;

           mathematically;

    K.E  = \frac{1}{2} x m v²

m is the mass

v is the velocity

  K.E  =  \frac{1}{2}  x 4 x 5  = 10J

5 0
3 years ago
Pls help i have 5 minutes
anyanavicka [17]

Number order:

5, 4, 3, 2, 1

7 0
4 years ago
Read 2 more answers
If mass is conserved during a nuclear reaction, then _____.
aleksley [76]
Then, the reaction does not have any kinetic energy
7 0
4 years ago
The white dwarf that remains when our sun dies will be mostly made of
expeople1 [14]

Answer:

Carbon and oxygen

Explanation:

White dwarfs are the stars which have used all their hydrogen and helium fuel and now exists with only carbon and oxygen in their core. Their size reduces up to one hundredth times of the size of their sun in early stages and yet they possess the same mass.  

Due to loss of fuels and impact of gravity, a young star collapses on itself leading to formation of dwarf star.

 

7 0
3 years ago
A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c
Lunna [17]

Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

so

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

so distance between the two second-order minima is 2.8 cm

6 0
3 years ago
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