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matrenka [14]
3 years ago
6

What is The common value for the speed of light in a vacuum

Physics
1 answer:
Talja [164]3 years ago
4 0
The most common value for the speed of light is 3*10^8 meters/second.

A more accurate number is <span>299 792 458 m/second, but that number is hardly ever used.</span>
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A physics student is conducting an optical experiment using an Optical Bench Kit available in many physics classrooms. A lit can
kobusy [5.1K]

Answer:

C) 10 cm

Explanation:

We shall first calculate the focal length of the mirror.

object distance u = 20 cm ( negative )

Image distance v = 12 cm ( negative )

using mirror formula

1/ v + 1 /u = 1/ f

-1/12  - 1/ 20 =1/ f

f =- 7.5 cm

In the second case

u = - 30 cm

f = - 7.5 cm

i / v + 1 / u = 1 / f

1 / v - 1/30 = - 1/ 7.5

v = -10 cm

Answer is C that is 10 cm

7 0
3 years ago
A sports car accelerates uniformly from rest to a speed of 87 mi/hr in 8s. Determine: a.The acceleration of the car
Furkat [3]

Answer:

Part a)

a = 4.86 m/s^2

Part b)

d = 155.52 m

Part c)

v_f = 48.6 m/s

Explanation:

As we know that car start from rest and reach to final speed of 87 mph

so we have

v_f = 87 mph = 38.88 m/s

now we have

Part a)

acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{38.88 - 0}{8}

a = 4.86 m/s^2

Part b)

distance moved by car with uniform acceleration is given as

d = \frac{v_f + v_i}{2} t

d = \frac{38.88 + 0}{2} 8

d = 155.52 m

Part c)

As we know that the car start from rest

so final speed after t = 10 s

v_f = v_i + at

v_f = 0 + (4.86)10

v_f = 48.6 m/s

3 0
3 years ago
How many total atoms are in one molecule of lithium nitrate, LiNO3? 1 3 5 7 6
Zanzabum
There are 5 atoms 1=LI 1=N 3=O
7 0
3 years ago
Read 2 more answers
What is the average velocity of a dragster that starts from rest at the starting line and finishes a race at 2600 m/s in 12 seco
xxMikexx [17]
Using the equation v(avg)=distance/time 
and the equation v=v(original)+a(t)
solve for acceleration
2600=0+a(12)
a=216.66666 m/s^2

Then, you use the equation
v^2=v(original)+2a*(change in x)
2600^2=2(216.666666)*change in x
6760000/2/216.666666 = 15600 meters which is the length of the race

Then using v(avg)=x/t
15600/12= 1300 m/s
7 0
3 years ago
A ball is thrown up at a speed of 20 m/s.
ioda

Given:

(Initial velocity)u=20 m/s

At the maximum height the final velocity of the ball is 0.

Also since it is a free falling object the acceleration acting on the ball is due to gravity g.

Thus a=- 9.8 m/s^2

Now consider the equation

v^2-u^2= 2as

Where v is the final velocity which is measured in m/s

Where u is the initial velocity which is measured in m/s

a is the acceleration due to gravity measured in m/s^2

s is the displacement of the ball in this case it is the maximum height attained by the ball which is measured in m.

Substituting the given values in the above formula we get

0-(20x20)= 2 x- 9.8 x s

s= 400/19.6= 20.41m

Thus the maximum height attained is 20.41 m by the ball

6 0
3 years ago
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