Dont ask me why...I cant really explain it...but if u have 1 repeating decimal, u put it over 9. If u have 2 repeating decimals, u put it over 99....3 repeating decimals, put it over 999.
Examples :
0.7 (repeating) = 7/9
0.27 (repeating) = 27/99 when simplified = 3/11 <===
0.444 (repeating = 444/999
Answer:
$199
Step-by-step explanation:
I = Prt
I = (1990)(0.05)(2)
I = 199
Answer:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have the following distribution given:
X 3 4 5 6
P(X) 0.07 0.4 0.25 0.28
We can calculate the mean with the following formula:

In order to find the variance we need to calculate first the second moment given by:

And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

4,408,730 = 4,000,000 + 400,000 + <span>8,000 + 700 + 30 </span>
Answer:
-0.25, -1/5, -2.5, -5, -10
Step-by-step explanation: