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3 years ago

What would happen to a eukaryotic cell if all it mitochondria were destroyed

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

5 0

Without that cell it would die.

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What is the oxidation number of chlorine in HClO4?

Elza [17]

CIO4-=-1

CI=4O=-1

O has a 2- oxidation change so

CI+4(-2)=-1

CI+(-8)=-1

CI=-1+8=7

So the oxidation number of chlorine is 7 in this case

8 0

3 years ago

Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

3 years ago

Calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral

Fynjy0 [20]

Moles of benzene

70/90=7/9=0.8mol

moles of CCl_4

30/154
0.2mol

Now

$\\ \rm\Rrightarrow \chi_{C_6H_6}$

$\\ \rm\Rrightarrow \dfrac{\chi_{C_6H_6}}{\chi_{sol^n}}$

$\\ \rm\Rrightarrow \dfrac{0.8}{0.8+0.2}$

$\\ \rm\Rrightarrow \dfrac{0.8}{1}$

$\\ \rm\Rrightarrow 0.8$

4 0

2 years ago

What is the mass of 1.0 × 10^9 molecules of aspartame?

Kobotan [32]

Answer:

294.3 g/mol b.

7 0

3 years ago

You drop the pendulum bob and it swings from point A to point C, and then back again. Eventually it slows down and stops, settli

maria [59]

B An enclosed pendulum is not acted on by air resistence or gravity. Plus, pendulum's in clocks are electronic (I think) so that's why it keeps moving back in forth. (at least i think so)

6 0

4 years ago